14= 3k-4
_ less than _ = -
3* k simplified= 3k
Answer:
100,000
Step-by-step explanation:
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Answer:
g(a+1)=5a+2
Step-by-step explanation:
so (a+1) is the value of x
you can write it like this:
x=a+1
using substitution, we can swap out all 'x's for 'a+1's. like so;
g(a+1)=5(a+1)-3 -- given
=5a+5-3 -- distribute
=5a+2 -- simplify!
Hope i helped! have a great day! please mark brainliest!!
Answer:
y = ½x - 14
Step-by-step explanation:
Given the linear equation, y = 3x - 4, where the <u>slope</u>, m = 3, and the <u>y-intercept</u> is (0, -4):
The slope of a linear equation represents the steepness of the line's graph. The higher the value of the slope, the steeper the line. Hence, the slope of the other line must be less than three, but is greater than zero: 0 < <em>m</em> < 3. (a negative slope will show a <em>declining</em> line).
Next, the vertical translation of the line involves changing the value of the parent graph's y-intercept. Since the prompt states that the equation must represent a downward vertical shift of 10 units, then the y-intercept of the other line must be (0, -14).
The linear equation that I have chosen that meets the requirements of the given prompt is: y = ½x - 14. <em>You're more than welcome to choose a different slope</em>, as long as it is less than 3, but is greater than 0 (must be a positive slope).
Attached is a graph of both equations, to demonstrate that the other equation represents a graph with a steeper slope than the original graph.
Answer:
C. 4(cos(300°) +i·sin(300°))
Step-by-step explanation:
The magnitude will be ...
magnitude = √(2^2 +(-2√3)^2) = √(4+12) = 4
The negative imaginary part puts the angle in the 4th quadrant. The answer choice with a magnitude of 4 and a 4th-quadrant angle is ...
4(cos(300°) +i·sin(300°))
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If you want to figure the angle, it will be ...
angle = arctan(Im()/Re()) = arctan(-2√3/2) = arctan(-√3) = -60°
The corresponding 4th-quadrant angle is 300°.
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<em>Comment on answer choices</em>
Answer choice A is <em>another representation of the same number</em>. Typically, we want the magnitude to be positive in polar form, so that answer can be avoided on those grounds.