53×2=106
2×53=106
106×1=106
1×106=106
Answer/Step-by-step explanation:
1. Side CD and side DG meet at endpoint D to form <4. Therefore, the sides of <4 are:
Side CD and side DG.
2. Vertex of <2 is the endpoint at which two sides meet to form <2.
Vertex of <2 is D.
3. Another name for <3 is <EDG
4. <5 is less than 90°. Therefore, <5 can be classified as an acute angle.
5. <CDE is less than 180° but greater than 90°. Therefore, <CDE is classified as an obtuse angle.
6. m<5 = 42°
m<1 = 117°
m<CDF = ?
m<5 + m<1 = m<CDF (angle addition postulate)
42° + 117° = m<CDF (Substitution)
159° = m<CDF
m<CDF = 159°
7. m<3 = 73°
m<FDE = ?
m<FDG = right angle = 90°
m<3 + m<FDE = m<FDG (Angle addition postulate)
73° + m<FDE = 90° (Substitution)
73° + m<FDE - 73° = 90° - 73°
m<FDE = 17°
We will take the common terms in the expressions-
Here in the expression, 3y is a common term.
So,
So, the answer is
You use the Pythagorean theorem which is a^2+b^2=c^2
So....
.8^2+.6^2=c^2
.64+.36=c^2
1=c^2
1=c becaaue the square root of one is one
