Okay so you split 9ab + 12ax - 6b - 8x
<span> into two 2-term polynomials </span>
+ 12ax + 9ab and - 6b - 8x
doesn't look that good to me so lest try other one :
9ab + 12ax and - 6b - 8x
looks good for now
<span> </span> Pull out from each binomial separately
9ab + 12ax = 3a • (3b + 4x)
- 6b - 8x = - 2 • (3b + 4x)
<span> </span> Add up to arrive at the desired factorization so now you have
<span> (3a - 2) • (3b + 4x)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Hope that Helped!</span>
Graph of y = -3/2x - 7 has a slope of -3/2.
For perpendicular lines the product of the slopes is -1.
m1m2 = -1
-3/2m2 = -1
m2 = -1/(-3/2) = 2/3
The required equation,
y - (-2) = 2/3(x - 3)
y + 2 = 2/3x - 2
y = 2/3x - 4
The two numbers are -6 and 7
<em><u>Solution:</u></em>
Given that eight times a number plus five times another number is -13
The sum of two numbers is 1
To find: the two numbers
Let the two numbers be "a" and "b"
From given information,
Eight times a number plus five times another number = -13
eight times a number "a" + five times another number "b" = -13
8a + 5b = -13 ---- eqn 1
Also given that sum of two numbers is 1
sum of two numbers = 1
a + b = 1 ---- eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "b"</u></em>
From eqn 2,
a = 1 - b ----- eqn 3
Substitute eqn 3 in eqn 1
8(1 - b) + 5b = -13
8 - 8b + 5b = -13
8 - 3b = -13
-3b = -13 - 8
-3b = -21
<h3>b = 7</h3>
Substitute b = 7 in eqn 3
a = 1 - 7
<h3>a = -6</h3>
Thus the two numbers are -6 and 7
Move variable to right -
-3Y=9-5x
Divide both sides by -3 -
y=-3+5 over 3 x 5/3 x(not right besides the 3 it is on the end)
x = 3,-1, multiplicity of 2.
Therefore, it is 4-degree polynomials. (considering that x = 3,-1,2,2)
We just convert these x-values into x-intercept form and convert again in standard form by multiplying.
(x-3)(x+1)(x-2)²
(x²-2x-3)(x²-4x+4)
(x⁴-4x³+4x²-2x³+8x²-8x-3x²+12x-12)
Thus the answer is x⁴-6x³+9x²+4x-12
