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2 years ago

Debug the following program.

Computers and Technology

1 answer:

mamaluj [8]2 years ago

4 0

Answer:

The debugged program is as follows:

A=2

B=2

For I=1 to 10

PRINT A

TEMP = A

A=B

B=TEMP+A

NEXT I

END

Explanation:

First, the value of B should be changed to 4 (because the second term of the sequence is 2

Next, change Display to Print because Q-basic uses the print keyword to display output

The sequence is not properly generated. So, I update that part of the program to:

For I=1 to 10

PRINT A

TEMP = A

A=B

B=TEMP+A

NEXT I

Lastly, the loop is controlled by variable I (not X).

So change NEXT X to NEXT I

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3 years ago

Consider the following algorithms. Each algorithm operates on a list containing n elements, where n is a very large integer.

DochEvi [55]

We have that the appropriate statement will be

An algorithm that accesses only the first 10 elements in the list, regardless of the size of the list. Which of the algorithms run in reasonable time

III only.

Option B

From the question we are told

Consider the following algorithms. Each algorithm operates on a list containing n elements, where n is a very large integer.

I. An algorithm that accesses each element in the list twice.

II. An algorithm that accesses each element in the list n times.

III. An algorithm that accesses only the first 10 elements in the list, regardless of the size of the list. Which of the algorithms run in reasonable time?

<h3>Algorithm </h3>

Generally In order to get admission to every thing in the list twice, the algorithm has to traverse the listing twice,

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And if the every factor is accessed n times, the listing will be traversed n time, which leads to n^2 get right of entry to operations.

If n is a very giant integer, each 2*n and n^2 are plenty larger.

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Therefore

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Option B

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2 years ago

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2 years ago

Hello,

tekilochka [14]

I think you should get used input

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3 years ago