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GarryVolchara [31]
3 years ago
6

When you write a check, why do you always begin writing the amount of the check as far to the left as you can?

Computers and Technology
1 answer:
Ivenika [448]3 years ago
5 0

Answer:

You start at the left without leaving any paces so no one can add any more numbers.

Explanation:

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The readline method reads text until an end of line symbol is encountered, how is an end of line character represented
zhannawk [14.2K]

Answer:

\n

Explanation:

readline() method is used to read one line from a file. It returns that line from the file.    

This line from the file is returned as a string. This string contains a \n at the end which is called a new line character.

So the readline method reads text until an end of line symbol is encountered, and this end of line character is represented by \n.

For example if the file "abc.txt" contains the lines:

Welcome to abc file.

This file is for demonstrating how read line works.

Consider the following code:

f = open("abc.txt", "r")  #opens the file in read mode

print(f.readline()) # read one line from file and displays it

The output is:

Welcome to abc file.    

The readline() method reads one line and the print method displays that line.                        

3 0
3 years ago
Given two 2x3 (2 rows, 3 columns) arrays of integer , x1 and x2, both already initialized , two integer variables , i and j, and
Gnesinka [82]
JAVA programming was employed...

What we have so far:
* Two 2x3 (2 rows and 3 columns) arrays. x1[i][j] (first 2x3 array) and x2[i][j] (second 2x3 array) .
* Let i = row and j = coulumn.
* A boolean vaiable, x1rules

Solution:

for(int i=0; i<2; i++)
{
   for(int j=0; j<3; j++)
   {
      x1[i][j] = num.nextInt();
   }
}// End of Array 1, x1.

for(int i=0; i<2; i++)
{
   for(int j=0; j<3; j++)
   {
      x2[i][j] = num.nextInt();
   }
}//End of Array 2, x2
This should check if all the elements in x1 is greater than x2:

x1rules = false;
if(x1[0][0]>x2[0][0] && x1[0][1]>x2[0][1] && x1[0][2]>x2[0][2] && x1[1][0]>x2[1][0] && x1[1][1]>x2[1][1] && x1[1][2]>x2[1][2])
{
   x1rules = true;
   system.out.print(x1rules);
}
else
{
   system.out.print(x1rules);
}//Conditional Statement
7 0
3 years ago
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