So if they eat 450 lb a day and you have a 3600 lb supply you simply divide 3600 by 450.
3600/450=8 days
so your final answer is 8 days.
Imx->0 (asin2x + b log(cosx))/x4 = 1/2 [0/0 form] ,applying L'Hospital rule ,we get
= > limx->0 (2a*sinx*cosx - (b /cosx)*sinx)/ 4x3 = 1/2 => limx->0 (a*sin2x - b*tanx)/ 4x3 = 1/2 [0/0 form],
applying L'Hospital rule again ,we get,
= > limx->0 (2a*cos2x - b*sec2x) / 12x2 = 1/2
For above limit to exist,Numerator must be zero so that we get [0/0 form] & we can further proceed.
Hence 2a - b =0 => 2a = b ------(A)
limx->0 (b*cos2x - b*sec2x) / 12x2 = 1/2 [0/0 form], applying L'Hospital rule again ,we get,
= > limx->0 b*(-2sin2x - 2secx*secx.tanx) / 24x = 1/2 => limx->0 2b*[-sin2x - (1+tan2x)tanx] / 24x = 1/2
[0/0 form], applying L'Hospital rule again ,we get,
limx->0 2b*[-2cos2x - (sec2x+3tan2x*sec2x)] / 24 = 1/2 = > 2b[-2 -1] / 24 = 1/2 => -6b/24 = 1/2 => b = -2
from (A), we have , 2a = b => 2a = -2 => a = -1
Hence a =-1 & b = -2
well the name of the phase for that is called freezing. I think that's we have to look for, maybe not, but I hope I helped
I WOULD SAY IT IS B>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
The tenths place would be the digit right after the decimal point, and we want to round 479.16 to the nearest tenths.
The number in the tenths place is 1. Now we have to decide if we're going to round up or down
- If the next digit is greater than or equal to 5, we round up (add 1 to the digit); if it isn't, then we round down (the digit stays the same).
The digit after the tenths place is "6", which is greater than 5. Thus, the "1" is rounded up to a "2"
Answer: 479.16 to the nearest tenths is 479.2.
Let me know if you need any clarifications, thanks!
~ Padoru
