June 19th 2006 specifically a monday
First you distribute the 3
(3x-12) (x+5)=0
then you set each equation equal to zero
3x-12=0 & x+5=0
then you solve for x
x =4, -5
1.-28×-28×-28+13×13×13+16×16×16
=21,952+2,197+4,096
=28,245.
2.12×12×12+-7×-7×-7+-5×-5×-5
=1,728+-343+-125
=1,260
Answer:
or 
Step-by-step explanation: