Answer:
<h3>72 units</h3>
Step-by-step explanation:
Given D,E, and F are collinear points and E is between D and F, then the expression DE + EF = DF.... 1 is true
If DE is six times the length of EF, then;
DE = 6DF
DF = DE/6 .....2
Substitute equation 2 into 1;
DE + EF = DF
DE + DE/6 = DF
find the LCM
(6DE+DE)/6 = DF
cross multiply
6DE+DE = 6DF
7DE = 6DF
Given DF = 84units
7DE = 6(84)
7DE = 504
Divide both sides by 7
7DE/7 = 504/7
DE = 72
Hence the length of segment DE is 72units
Answer:
12x^2-25x-7
Step-by-step explanation:
Multiply each term by its counterpart in the parenthesis.
4x*3x and 4x*-7
1*3x and 1*-7
This gives you 12x^2-4x*7+3x-7 when the like terms are combined.
Collect the like terms, which will give you 12x^2-25x-7
Answer:
Is this a multiple choice question or do you actually have to fill it in? I think it might be 4
Step-by-step explanation:
58
Sorry if I got that wrong
Answer:
Substitute point (4, 8)
y = y1 + m(x - x1)
y = 8 + m(x - 4)
y = 8 + mx - 4m
let m = 3 (It can be anything) Substitute m into equation:
y = 8 + (3)x - 4(3)
y = 2x - 4
