Is the quotient for 41 / 0.8 greater or less than 41? Explain.

Manuel is filling water balloons at a constant rate of 3 water balloons per minute. With the given information, which of these s

Gnesinka [82]

Okay. Well it's C. 1/2 hour is 30 mins, so 30 times 3 is 90. Just as the answer states, 90 water balloons filled after 1/2 of an hour.

6 0

3 years ago

The difference of two numbers is 90 and their quotient is 10

bija089 [108]

To solve this, set up two equations using the information you're given. Let's call our two numbers a and b:
1) Difference of two numbers is 90
a - b (difference of two numbers) = 90

2) The quotient of these two numbers is 10
a/b (quotient of the two numbers) = 10

Now you can solve for the two numbers.
1) Solve the second equation for one of the variables. Let's solve for a:
a/b = 10
a = 10b

2) Plug a =10b into the first equation and solve for the value of b:
a - b = 90
10b - b = 90
9b = 90
b = 10

3) Using b = 10, plug it back into one of the equations to find the value of a. I'll plug it back into the first equation:
a - b = 90
a - 10 = 90
a = 100

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Answer: The numbers are 100 and 10

3 0

3 years ago

Consider testing H^0: u=20 against H^a: u<20 where u is the mean number of latex gloves used per week by all hospital employe

iragen [17]

Answer:

Part a: P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=46-1=45$

Since is a one sided test the p value would be:

$p_v =P(t_{(45)}$

Part b: Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can conclude that the true mean is not lower than 20 at 1% of signficance.

a. There is insufficient evidence to reject h^0

Step-by-step explanation:

Data given and notation

$\bar X=19.1$ represent the sample mean

$s=11.8$ represent the sample standard deviation

$n=46$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is lower than 20, the system of hypothesis would be:

Null hypothesis: $\mu \geq 20$

Alternative hypothesis: $\mu < 20$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{19.1-20}{\frac{11.8}{\sqrt{46}}}=-0.517$

Part a: P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=46-1=45$

Since is a one sided test the p value would be:

$p_v =P(t_{(45)}$

Part b: Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can conclude that the true mean is not lower than 20 at 1% of signficance.

a. There is insufficient evidence to reject h^0

5 0

2 years ago

[NO WRONG ANSWERS!!!] What is the sum of the following equation? 89x+5y+1x+5y

mixas84 [53]

Answer:

90x+10y

Step-by-step explanation:

Add 89 and 1

Add 5 and 5

90x+10y in this order

3 0

3 years ago

Read 2 more answers

Tell if each is an arithmetic sequence. If it is, give the common difference.

taurus [48]

Answers:

5.) Yes it is, you add each one to itself to get the next number

6.) Yes, you subtract 5 from each number

7.) yes, you add 1.50 to each number

8.) Yes, you add 50 to each number

9.) No, they do not follow a pattern

10) Yes, you divide by 5 every time.

5 0

2 years ago