The solution for this problem would be:
f'(x) = 1 - 1/x^2 = (x^2 - 1)/x^2
is positive where |x| > 1
hence (-inf, -1) and (1, inf) are the regions in which f' is positive and therefore f is increasing.
Therefore, the answer is (-infinity,-1] U [1,infinity).
Hello,
x^3-12x²-2x+24=x²(x-12)-2(x-12)=(x-12)(x²-2)
Answer D
Answer:
2x + 3y = 6
Step-by-step explanation:
obtain the equation in slope- intercept form
y = mx + c ( m is the slope and c the y-intercept )
here m = - 
and c = 2
y = - x + 2 ← in slope-intercept form
multiply all terms by 3 to eliminate the fraction
3y = - 2x + 6 ( add 2x to both sides )
2x + 3y = 6 ← in standard form
Answer:
Step-by-step explanation:
complex roots always occur in pairs.
roots are 1,2-2i,2+2i
P(x)=a(x-a)(x-b)(x-c)
P(x)=1(x-1)[x-(2-2i)][x-(2+2i)]
=1(x-1)[(x-2)+2i][(x-2)-2i]
=(x-1)[(x-2)²-(2i)²]
=(x-1)[(x-2)²-4i²]
=(x-1)[x²-4x+4-4(-1)]
=(x-1)[x²-4x+4+4]
=(x-1)[x²-4x+8]
=x³-4x²+8x-x²+4x-8
=x³-5x²+12x-8
The answer should be letter A
