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love history [14]
3 years ago
7

A rectangle with area 36 square inches has a length that is 3 less than 3 times the width. Find the length and the width of the

rectangle.
Mathematics
1 answer:
OlgaM077 [116]3 years ago
4 0

Answer:

length = 9 in ; width = 4 in

Step-by-step explanation:

1) formula of the area of a rectangle

A = base x width

2) write an equation with the given informations:

w x (3w-3) = 36

3) solve the equation

-  multiply W by 3w and -3

3w^2 -3w = 36

- divide the two members by 3

w^2 - w = 12

- add up -12 at the two members

w^2-w -12 = 12 -12

w^2 - w - 12 = 0

- find two numbers whose sum is -1 and whose product is -12 and factorise the equation

(w-4)(w+3) = 0

- find the two solutions

w-4 = 0

w = 4

w+3 = 0

w = -3

4)remember that a length can’t be negative.

w = 4 is the only solution

5) find the length

4x3 - 3 = 9

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r = c/2pi

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c= pi*d

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c = 2*r*pi

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2 years ago
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Antonio ran 129 laps at the park. Alan ran 20% more than that. how many laps did Alan run
Colt1911 [192]

Answer:

154.8

Step-by-step explanation:

20% is equal to 20/100= 0.20. So, 0.20 multiplied by 129 will give you 20% of 129 which is 25.8. If Alan ran 20% more then you add 25.8 to 129 which gives you an answer of 154.8.

Equation: 20/100= 0.2

                0.2* 129= 25.8

                25.8+129= 154.8

Alan ran 154.8 laps.

3 0
3 years ago
students set up 6 rows of seats for a music concert. they put 6 seats in each row. what is the total number of seats? solve this
Mariulka [41]

Answer:

36

Step-by-step explanation:

becuase each row has 6 in them and there are 6 rows so 36 is the final answer

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2 years ago
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Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 76.676.6
faltersainse [42]

Answer:

Step-by-step explanation:

Researchers measured the data speeds for a particular smartphone carrier at 50 airports.

The highest speed measured was 76.6 Mbps.

n= 50

X[bar]= 17.95

S= 23.39

a. What is the difference between​ the carrier's highest data speed and the mean of all 50 data​ speeds?

If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps

b. How many standard deviations is that​ [the difference found in part​ (a)]?

To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation

Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations

c. Convert the​ carrier's highest data speed to a z score.

The value is X= 76.6

Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51

d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly​ high, is the​ carrier's highest data speed​ significant?

The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.

I hope it helps!

3 0
3 years ago
Solve 12x-5>-2 please
Stells [14]

Answer:

x >  \frac{1}{4}

Step-by-step explanation:

12x - 5 >  - 2

Lets add +5 in both the sides.

=  > 12x - 5 + 5 >  - 2 + 5

=  > 12x > 3

Now lets divide 12 on both the sides.

=  >  \frac{12x}{12}  >  \frac{3}{12}

=  > x >  \frac{1}{4}

8 0
3 years ago
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