let h= 3, k=-2
radius (r) = 11 ,then
(x-h)^2 + ( y-k)^2 = r^2
(x-3)^2 + ( y+2)^2 = 11^2
x^2 -6x +9 + y^2 +4y +4 = 121
x^2 + y^2 - 6x +4y -108 = 0 is the required eq
I’m not an expert at this but my guess is 45 degrees. Can you let me know what the correct answer was?
Option B:

Solution:


Take LCM of the denominators and Make the denominators same.
LCM of 16, 320, 1 = 320


All the denominators are same, so you can write in one fraction.

Do cross multiplication.


Add 9280 on both sides of the equation.

Subtract 20x on both sides of the equation.

Let y = f(x).

Hence Option B is the correct answer.
Hi there!
To solve this problem, we need to divide the total amount of tables by the amount of students:
40 / 10 = 4
So, we need 4 tables to seat 40 students.
Hope this helps!
Answer:
sup have you googled it?
Step-by-step explanation:
Mass of elephant/mass of ant = 8x10^6/4x10^-3 = 2x10^9. Therefore, mass of elephant = 2x10^9 times mass of ant.