Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
Answer:
20%
Step-by-step explanation:
To find the percent decrease, we do old number subtracted from the new numbers over old.
We do
40 - 32 = 8
Then we put the 8 over the old and get
8/40
In percentage form it would be 20%
Answer: D
take 5/15 and simplify to 3/1
Should be C. 1/19. because if there's 20 maebles in the bag and without replacing the marble then it actually would be 2/18
