Answer:
let the equal sides of the triangle be of length "a" . let the angle between these two sides be " x ". Then drop a perpendicular from the vertex to the base. now u have 2 similar triangles .the angle between the perpendicular and one of the equal sides is now (x/2) . length of perpendicular = a cos(x/2) length of base = 2a sin(x/2) . area of triangle = (1/2) 2sin(x/2) cos(x/2) a-square
= (1/2) (sin x) a-square
Answer:
The dimensions of the box are:
Length = 11.53cm
Breadth = 11.53cm
Height = 11.53cm
Step-by-step explanation:
The volume of the box can be calculated with this formula:
The volume of the box = area of square base X height of the box.
We are given that the length of one side of the square base is = x cm, and its height is h cm.
Area of square base =
The surface area of the box will be minimized if the height of the box, is the same as its length. hence, we can take the height of the box to be x cm also.
In this case, the volume of the box will be
from this,
There fore, the box has its length, height, and width all having the same values.
The dimensions of the box are:
Length = 11.53cm
Breadth = 11.53cm
Height = 11.53cm