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PIT_PIT [208]
2 years ago
6

I have two equationsa-2b=8 and 4a+3b=21 how can you solve one of these for a​

Mathematics
1 answer:
Olenka [21]2 years ago
6 0

Step-by-step explanation:

You could find a number that can be multiplied by 2 and a number for a that when you subtract from the number that you multiplied by 2 can give the result of 8.

Example:

a-2b=8: a=12-2•2=8

12-4=8

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Use distributive property:

-6x+12

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How would you simplify 5-6w-4+7w?
Natasha2012 [34]
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2 years ago
200 meters
Katyanochek1 [597]

Answer:

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7 0
2 years ago
Please solve the eqution<br> Cos4x + cos2x - 2 =0
horrorfan [7]

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We know that:

cos2x = 1-2cos^2 x

==> cos4x = 1-2cos^2 (2x)

Now substitute:

==> 1-2cos^2 (2x) = cos2x

==> 2cos^2 (2x) + cos2x - 1 = 0

Now factor:

==> (2cos2x -1)(cos2x + 1) = 0

==> 2cos2x -1 = 0 ==> cos2x =1/2 ==> 2x= pi/3

==> x1= pi/6 , 7pi/6

==> x1= pi/6 + 2npi

==> x2= 7pi/6 + 2npi

==> cos2x = -1 ==> 2x= pi ==> x3 = pi/2 + 2npi.

<span>==> x= { pi/6+2npi, 7pi/6+2npi, pi/2+2npi}</span>

6 0
3 years ago
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