∑ 4 * 5^(i-1) = 4 + 20 + 100 + 500 = 624
∑ 3 * 4^(i-1) = 3 + 12 + 48 + 192 + 768 = 1,023
∑ 5* 6^(i-1) = 5 + 30 = 35
∑ 5^(i-1) = 1 + 5 + 25 + 125 = 156
Answer:
∑ (i=1, 2) 5 * 6^(i-1) < ∑ (i=1, 4) 5^(i-1) < ∑ (i=1, 4) 4 * 5^(i-1) <
< ∑ (i=1, 5) 3 * 4^(i-1)
The question is incomplete as the cost price isn't given. However, taking the cost price as x :
Answer:
Kindly check explanation
Step-by-step explanation:
Given :
A car costs$cents when new. It was sold for four fifths of its cost price. How much money was lost on the car.
Let :
Cost price when new = x
Cost price when sold = 4/5 * cost price when new
Cost when sold = 4/5 of x = 4x/5
Amount of money lost on the car = (Cost price of car when new - Cost of car when sold)
Hence,
Amount of money lost on the car = (x - 4x/5)
x - 4x/5 = (5x - 4x) / 5 = x / 5
To obtain the exact price, kindly input the omitted cost when new for x.
Answer:17 out of 20
Step-by-step explanation:
Principal: $49,000
Depreciation Rate: 50%
Depreciation Time: 5 years
Exponential Function: y = 49,000 (0.50)^x
Plug it in: y = 49,000 (0.50)^4
0.5^4= 0.0625
0.0625 x 49,000 = 3062.5
Value of Car after 20 years: 3062.5
Now, we need to find out how much the car decreases in ONE year.
Half of 3062.5 = 1531.25
1531.25/5 = 306.25
3062.5 - 306.25 = 2756.25
Value of car after 21 years: $2756 ---> 2800 (nearest hundred dollars my bad)
Hope this helps! Have a great day!
Answer:
5 hours
Step-by-step explanation:
