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Ber [7]
3 years ago
13

A box of candy was divided into three bottles P, Q and R in the ratio 9:4:11. If, instead, the candy had been divided equally be

tween them, there would be 21 fewer pieces of candy in bottle R. How many pieces of candy were there in the box?​
Mathematics
1 answer:
pishuonlain [190]3 years ago
6 0

Step-by-step explanation:

Let there be x pieces of candy in the box.

In the original settings, bottle R gets

\frac{11}{9+4+11}x= \frac{11}{24}x

candies.

If the candies are equally distribued, then bottle R gets he h

\frac{x}{3}

candies.

Now,

\frac{11}{24}x- \frac{1}{3}x=21

\frac{x}{8}=21

x=168

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