A box of candy was divided into three bottles P, Q and R in the ratio 9:4:11. If, instead, the candy had been divided equally be

Question

3 years ago

13

tween them, there would be 21 fewer pieces of candy in bottle R. How many pieces of candy were there in the box?

1 answer:

pishuonlain [190] · Answer 1 · 2022-04-09T22:59:10+03:00

6 0

Step-by-step explanation:

Let there be x pieces of candy in the box.

In the original settings, bottle R gets

$\frac{11}{9+4+11}x= \frac{11}{24}x$

candies.

If the candies are equally distribued, then bottle R gets he h

$\frac{x}{3}$

candies.

Now,

$\frac{11}{24}x- \frac{1}{3}x=21$

$\frac{x}{8}=21$

$x=168$