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3 years ago

13

A box of candy was divided into three bottles P, Q and R in the ratio 9:4:11. If, instead, the candy had been divided equally be

tween them, there would be 21 fewer pieces of candy in bottle R. How many pieces of candy were there in the box?

1 answer:

pishuonlain [190]3 years ago

6 0

Step-by-step explanation:

Let there be x pieces of candy in the box.

In the original settings, bottle R gets

$\frac{11}{9+4+11}x= \frac{11}{24}x$

candies.

If the candies are equally distribued, then bottle R gets he h

$\frac{x}{3}$

candies.

Now,

$\frac{11}{24}x- \frac{1}{3}x=21$

$\frac{x}{8}=21$

$x=168$

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3 years ago

A sporting goods store sells right-handed and left-handed baseball gloves. In one month, 12 gloves were sold for a total revenue

stepladder [879]

Answer:

$9$ right-handed gloves and $3$ left-handed gloves were sold.

Step-by-step explanation:

Given: In one month, $12$ gloves were sold for a total revenue of $\$561$ .

right-handed gloves cost $\$45$ and left-handed gloves cost $\$52$ .

To find: How much of each type of gloves did they sell?

Solution: Let they sell $x$ right-handed gloves, and $y$ left-handed gloves.

Now, cost of each right-handed gloves $=\$45$

cost of each left-handed gloves $=\$52$

Total revenue $=\$561$

So, we get

$45x+52y=561\:\:\:...(i)$

Also, in a month $12$ gloves were sold.

So, we get

$x+y=12\:\:\:...(ii)$

Now, from $(ii)$ we get, $x=12-y$ .

Putting $x=12-y$ in equation $(i)$ , we get

$45(12-y)+52y=561$

$\implies 540-45y+52y=561$

$\implies7y=561-540$

$\implies7y=21$

$\implies y=\frac{21}{7}$

$\implies y=3$

Now, putting $y=3$ in equation $(ii)$ , we get

$x+3=12$

$\implies x=12-3$

$\implies x=9$

Hence, $9$ right-handed gloves and $3$ left-handed gloves were sold.

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3 years ago

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2 years ago

I need help i will give brainiest question in screenshot

Thepotemich [5.8K]

Answer:

ok so first you have to know what a reflectiin along 180 is

) A point P(x,y)P(x,y) is rotated 180180 degrees about the origin, then reflected over the y-axis. What is the resulting image of PP?

My conjecture: (−x,y)(−x,y) but I don't quite agree with it graphically. I'm having trouble with what exactly a 180 degree rotation about the origin simply is.

2) A point P(x,y)P(x,y) is reflected over the y-axis and then rotated 180 degrees about the origin. What is the resulting image?

Is this the same thing as 1?

3) A point A(x,y)A(x,y) is reflected over the line y=xy=x and then reflected over the y-axis. What is the resulting image of A?

My conjecture: (−y,x)(−y,x)

4) A point A(x,y)A(x,y) is reflected over the lines y=−xy=−x and then reflected over the y-axis. What is the resulting image of A?

My conjecture: (y,−x)

ok you need to know what thouse meen

Step-by-step explanation:

)If P(x1,y1)P(x1,y1) is rotated angle ϕϕ about O(a,b)O(a,b) to P′(x′,y′)P′(x′,y′)

we have |OP|=|OP′||OP|=|OP′| and |arctanmOP−arctanmOP'|=ϕ|arctan⁡mOP−arctan⁡mOP'|=ϕ

By atan(z)(z) I imply atan2

(2)If P(x1,y1)P(x1,y1) is reflected over L:ax+by+c=0L:ax+by+c=0 and the resulting image of PP is Q(x2,y2) (1)Q(x2,y2) (1)

We have R

so i hope thiz helprs you

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3 years ago

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3 years ago