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3 years ago

D 5/3 Couldn’t fit in pic

Mathematics

2 answers:

labwork [276]3 years ago

6 0

Answer:

Step-by-step explanation:

You can just move upper y equation and it will be:

6x+3(3x-5)=15

6x+9x-15=15

15x-15=15

15x=30

x=2

kolezko [41]3 years ago

4 0

Answer:

Try the website, MATH

WAY

type in your equations

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Will give branlest for any help that is right

devlian [24]

Answer:

7x+3=2x-6 #4

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Medical scientists study the effect of acute infection on tissue-specific immunity. In a collection of experiments under the sam

Serjik [45]

Answer:

The 95% confidence interval for the true proportion of mice that will test positive under similar conditions is (0.5291, 0.6429).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

In a collection of experiments under the same conditions, 44 of 75 mice test positive for lymphadenopathy. This means that $n = 75$ and $\pi = \frac{44}{75} = 0.586$ .

Compute a 95% confidence interval for the true proportion of mice that will test positive under similar conditions.

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.586 - 1.96\sqrt{\frac{0.586*0.414}{75}} = 0.5291$

The upper limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.586 + 1.96\sqrt{\frac{0.586*0.414}{75}} = 0.6429$

The 95% confidence interval for the true proportion of mice that will test positive under similar conditions is (0.5291, 0.6429).

7 0

3 years ago

Burka [1]

Answer:

Step-by-step explanation:

$F \alpha \frac{1}{d^{2} }$

$F = \frac{K}{d^{2} }$

When F = 18; d = 2

$18 = \frac{K}{2^{2} }$

$18 = \frac{K}{4}$

Cross multiply;

18 x 4 = K

72 = K

There the equation connecting F and $d^{2}$ is

$F = \frac{72}{d}$

Now, Find F when d = 6

All you do is to substitute d = 6 in to $F = \frac{72}{d}$

$F = \frac{72}{6}$

Therefore;

F = 12

Please mark me brainiest if correct.

6 0

3 years ago

RED YOU ARE VERY SUS

Allisa [31]

Answer:

YES YES HE VENTED ITS NOT ME DONT WORRY

7 0

3 years ago

Read 2 more answers

A long year end status report for work is 108 pages long. You need to print 19 copies for a meeting next week. How much is the p

maks197457 [2]

A total of
108*19 = 2052
pages will be printed. We suppose paper will be purchased in reams of 500 pages each, so
ceiling(2052/500) = ceiling(4.104) = 5
reams will be needed. The the cost will be
(5 reams)*($3.69/ream) = $18.45

The paper for the reports will cost $18.45.

7 0

3 years ago