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Montano1993 [528]

2 years ago

10

What is 2x-40y=73 and 7x+65y=332?

2 answers:

Mazyrski [523]2 years ago

8 0

I hope you understand your answer is this

Romashka [77]2 years ago

4 0

$\large\mathfrak{{\pmb{\underline{\orange{Given }}{\orange{:}}}}}$

$2x - 40y = 73...(i)$

$7x + 65y = 332...(ii)$

$\large\mathfrak{{\pmb{\underline{\pink{To\:find }}{\pink{:}}}}}$

The values of $x$ and $y$ .

$\large\mathfrak{{\pmb{\underline{\green{Solution }}{\green{:}}}}}$

$x=43.96$ and $y = 0.373$ .

$\large\mathfrak{{\pmb{\underline{\purple{Step-by-step\:explanation}}{\purple{:}}}}}$

Let us solve this by substitution method.

From $eqn.\:(i),\:we\:have$

↬ $2x - 40y = 73$

↬ $2x = 73 + 40y$

↬ $x = \frac{73 + 40y}{2}...(iii) \\$

Substituting the value of $x$ in $eqn.\:(ii)$ gives us

↬ $7( \frac{73 + 40y}{2} ) + 65y = 332 \\$

↬ $\frac{511 + 280y}{2} + \frac{65y \times 2}{1 \times 2} = 332 \\$

↬ $\frac{511 + 280y + 130y}{2} = 332 \\$

↬ $410y + 511 = 332 \times 2$

↬ $410y = 664 - 511$

↬ $y = \frac{153}{410} \\$

↬ $y = 0.373$

Now, plug the value of $y$ in $eqn.\:(i)$

↬ $2x - 40 \times 0.373 = 73 \\$

↬ $2x - 14.92= 73$

↬ $2x = 73 +14.92$

↬ $x = \frac{87.92}{2} \\$

↬ $x = 43 .96$

Therefore, the values of $x$ and $y$ are $\boxed{ 43.96 }$ and $\boxed{ 0.373 }$ respectively.

$\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35}}}}}$

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sasho [114]

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Step-by-step explanation:

For this case we know that for 1938 the minimum wag was 0.25 per hour and for 2009 the new minimum wag was 7.25 per hour.

We want to find an exponential function like this:

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Where y represent the value for the minimum wage and x represent the number of years since 1938.

USing the first condition given we know that for 1938 the value of x = 0 and w ehave:

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Now using the second condition we know that x = 2009-1938 =71 so then we have this:

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$b = 29^{1/71}= 1.04856934$

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$y = 0.25 (1.04856934)^x$

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