Question

What is 2x-40y=73 and 7x+65y=332?

Answer 1

I hope you understand your answer is this

Answer 2

$\large\mathfrak{{\pmb{\underline{\orange{Given }}{\orange{:}}}}}$

$2x - 40y = 73...(i)$

$7x + 65y = 332...(ii)$

$\large\mathfrak{{\pmb{\underline{\pink{To\:find }}{\pink{:}}}}}$

The values of $x$ and $y$.

$\large\mathfrak{{\pmb{\underline{\green{Solution }}{\green{:}}}}}$

$x=43.96$ and $y = 0.373$.

$\large\mathfrak{{\pmb{\underline{\purple{Step-by-step\:explanation}}{\purple{:}}}}}$

Let us solve this by substitution method.

From $eqn.\:(i),\:we\:have$

↬$2x - 40y = 73$

↬$2x = 73 + 40y$

↬$x = \frac{73 + 40y}{2}...(iii)$

Substituting the value of $x$ in $eqn.\:(ii)$ gives us

↬$7( \frac{73 + 40y}{2} ) + 65y = 332$

↬$\frac{511 + 280y}{2} + \frac{65y \times 2}{1 \times 2} = 332$

↬$\frac{511 + 280y + 130y}{2} = 332$

↬$410y + 511 = 332 \times 2$

↬$410y = 664 - 511$

↬$y = \frac{153}{410}$

↬$y = 0.373$

Now, plug the value of $y$ in $eqn.\:(i)$

↬$2x - 40 \times 0.373 = 73$

↬$2x - 14.92= 73$

↬$2x = 73 +14.92$

↬$x = \frac{87.92}{2}$

↬$x = 43 .96$

Therefore, the values of $x$ and $y$ are $\boxed{ 43.96 }$ and $\boxed{ 0.373 }$ respectively.

$\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35}}}}}$