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galina1969 [7]
3 years ago
7

Area for a kite I don’t know how to find the area pls help

Mathematics
1 answer:
dusya [7]3 years ago
7 0

Answer:

63.966

Step-by-step explanation:

Area of a kite is

\frac{pq}{2}

where p and q are the diagonals.

The horinzontial diagonal is 8.

We need to find the vertical diagonal length.

The top triangle diagonal measure is

{4}^{2}  +  {x}^{2}  =  {7}^{2}

16 +  {x}^{2}  = 49

{x}^{2}  = 33

x =  \sqrt{33}

The bottom triangle diagonal measure is

{4}^{2}  +  {x}^{2}  =  {11}^{2}

1 6 +  {x}^{2}  = 121

{x}^{2}  = 105

x =  \sqrt{105}

Add the two diagonals.

\sqrt{105}  +  \sqrt{33}

Substitute this in for the formula

\frac{8 \times ( \sqrt{105}  + \sqrt{33}  }{2}

Which simplified gu

Ives us

63.966

Round if neededd.

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Square lMNO is shown in the diagram below what are the coordinates of the midpoint of a diagonal LN
sashaice [31]

Answer:

The coordinates of the midpoint of LN are (-2\frac{1}{2},4\frac{1}{2})

answer (4)

Step-by-step explanation:

* Lets explain how to find the midpoint of a line

- The coordinates of the midpoint of a line whose endpoints are (x1 , y1)

 and (x2 , y2) are x=\frac{x_{1}+x_{2}}{2},y=\frac{y_{1}+y_{2}}{2}

∵ LMNO is a square

∵ The coordinates of point L are (-6 , 1)

∵ The coordinates of point N are (1 , 8)

- Let the coordinates of point L are (x1 , y1) , the coordinates of point

 N are (x2 , y2) and the coordinates of the midpoint of LN are (x , y)

∴ x1 = -6 , x2 = 1 and y1 = 1 , y2 = 8

- Use the rule of the midpoint above to find the midpoint (x , y)

∵ x=\frac{-6+1}{2}=\frac{-5}{2}=-2\frac{1}{2}

∵ y=\frac{1+8}{2}=\frac{9}{4}=4\frac{1}{2}

∴ The coordinates of the midpoint are (-2\frac{1}{2},4\frac{1}{2})

* The coordinates of the midpoint of LN are (-2\frac{1}{2},4\frac{1}{2})

8 0
3 years ago
Help please !!!!! asap
AnnyKZ [126]
The answer: m∡BCD = 130° .
_____________________________________
Explanation:
______________________________
m∡BCD = 9x - 5 = our answer.
_____________________________
Note: (9x - 5) + (m∡C IN Δ  ACB)= 180 ;
____________________________
Reason: all angles on straight line add up to 180.
___________________________
Note: In Δ ACB; m∡A + m∡B + m∡c = 180.
_________________________________________
Reason: All three angles in any triangle add up to 180.
__________________________________________
Given  Δ ACB, we are given:
_____________
m∡C= ?
m∡B = (4x + 5)
m∡A = 65
_____________________
So, given  Δ ACB; m∡A + m∡B + m∡c = 180;
 →Plug in our known values and rewrite:
___________________________________
Given  Δ ACB; 65 + 4x + 5 + (m∡c) = 180;
  →Simplify, and rewrite:
___________________________________
Given  Δ ACB; 4x + 70 + (m∡c) = 180;
  →Subtract "70" from each side of the equation; and rewrite:
___________________________________
Given  Δ ACB; 4x + (m∡C) = 110;
   →Subtract "4x" from EACH SIDE of the equation; to isolate: "(m∡c)" on one side of the equation; and "solve in terms of "(m∡C)" ;
______________________________________________
Given Δ ACB' m∡C = 110 - 4x ;
__________________________________________
So, we know that: (110 - 4x) + (9x - 5) = 180; (since all angles on a straight line add up to 180.
____________________
We can solve for "x".
____________________
(110 - 4x) + (9x - 5) = 180;
________________________
Rewrite as: 
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(110 - 4x) + 1(9x - 5) = 180 ;  (Note: there is an implied coefficient of "1"; since anything multiplied by "1" equals that same value).
_______________________
Note the "distributive property of multiplication": 
_________________
 a*(b+c) = ab + ac ; AND:
 a*(b - c) = ab - ac .
_______________________
So, +1(9x - 5) = (+1*9x) - (+1*5) = 9x - 5 ;
__________________________
So we can rewrite:
___________________
(110 - 4x) + (9x - 5) = 180 ; as:
________________________
110 - 4x + 9x - 5 = 180 ;  We can simplify this by combining "like terms" on                                         the "left-hand side" of the equation:
_________________________________________________
110 - 5 = 105 ;
-4x + 9x = 5x; 
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So, rewrite as: 5x + 105 = 180;  Subtract "105" from EACH side; to get:
_____________________________________
 5x  = 75 ; Now, divide each side of the equation by "5"; 
              to get: x = 15.
_____________________________________________
Now, we want to know: m∡BCD; which equals:
_____________________________________________
 9x - 5 ;  let us substitute "15" for "x"; and solve:
______________________
9x - 5 = 9*(15) - 5 = 135 - 5 = 130.
_____________________________
The answer: m∡BCD = 130°
________________________
6 0
3 years ago
The point A(–1, 4) is translated five units right and three units down. Which rule describes the translation?
Gnom [1K]

ur answer is B Step-by-step explanation:

I said so just do it

6 0
3 years ago
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???pls help i'm not that smart thank you
Sauron [17]
Answer:
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4 0
3 years ago
V=n/t+10<br> solve for n
AnnZ [28]

Answer:

Lets isolate

v-10=n/t

negate the right side

t(v-10)= n

8 0
3 years ago
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