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dedylja [7]
3 years ago
7

Solve for − ∣ x − 2 ∣ + 4 ≤ 0

Mathematics
1 answer:
MakcuM [25]3 years ago
5 0

Answer:

x ≥ 6 or x ≤ -2

Step-by-step explanation:

- I x - 2 I + 4 ≤ 0

- I x - 2 I ≤ -4

I x - 2 I ≥ 4

x - 2 ≥ 4  or  x - 2 ≤ -4

x ≥ 6  or x ≤ -2

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PLZ ASAP! but take your time to solve it.
gizmo_the_mogwai [7]

Answer:

20

Step-by-step explanation:

6 0
3 years ago
FRACTIONS
Vladimir79 [104]

The complete fraction is 24/30=4/5

<h3>How to create an equivalent fraction?</h3>

The expression is given as:

blank over 30=4/5

Represent the blank with x.

So, we have:

x/30=4/5

Multiply both sides by 30

x = 30 * 4/5

Evaluate

x = 24

Substitute x = 24 in x/30=4/5

24/30=4/5

Hence, the complete fraction is 24/30=4/5

Read more about fractions at:

brainly.com/question/10354322

#SPJ1

3 0
2 years ago
Answer the 5 questions Listed below Please Show your Work
Zolol [24]
(6 1/3) / (5/6) = (19/3) / (5/6) = 19/3 * 6/5 = 114/15 = 38/5

3 - 7^2 + 3 * 4^2
3 - 49 + 3 * 16
3 - 49 + 48
- 46 + 48
2

(7b - 2) / (-a + 1)....a = -2, b = 3, c = -1/3
where is he c in this equation ? Because if I just use a and b, my answer is not an answer choice

(7b - 10) / (a - 1)...a = -1, b = 5, c = -2/3
same as before...where is the c in this equation

V = (pi) r^2* h
V = (pi)(5^2)(7)
V = (pi)(25)(7)
V = 175(pi)








5 0
3 years ago
Solve the inequality.<br><br> 2(b – 8) &gt; 12
sashaice [31]
2b-16>12 add the 16 2b>28 then divide by 2
 b>14


5 0
3 years ago
Read 2 more answers
At what angle does a diffraction grating produce a second-order maximum for light having a first-order maximum at 20.0 degrees?
hichkok12 [17]

Answer:

At 43.2°.

Step-by-step explanation:

To find the angle we need to use the following equation:

d*sin(\theta) = m\lambda

Where:

d: is the separation of the grating

m: is the order of the maximum

λ: is the wavelength

θ: is the angle              

At the first-order maximum (m=1) at 20.0 degrees we have:

\frac{\lambda}{d} = \frac{sin(\theta)}{m} = \frac{sin(20.0)}{1} = 0.342

Now, to produce a second-order maximum (m=2) the angle must be:

sin(\theta) = \frac{\lambda}{d}*m

\theta = arcsin(\frac{\lambda}{d}*m) = arcsin(0.342*2) = 43.2 ^{\circ}

Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.    

I hope it helps you!                                                        

6 0
3 years ago
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