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3 years ago

Express 40% as a fraction in simplest form

Mathematics

1 answer:

bonufazy [111]3 years ago

7 0

2/5.

40/100=4/10=2/5

Enjoy

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Please help with all of these 5 points per question

liberstina [14]

Answer:

1. C = $100 = .25(m)

2. C = $150

3. 800 = m

Step-by-step explanation:

1. C = $100 (flat fee rate) + .25m

2. c = $100 + .25(200 miles)

↓

c = $100 + 50

↓

c = 150

3. 300 = 100 + .25(m)

-100 -100 (subtract on both sides)

--------------------------------

200 = .25(m)

------------------- (divide by .25 to get m by itself)

.25

Therefore being 800 = m

5 0

4 years ago

Lindsay says all numbers that are multiples of 4 have 2 as a factor. Is lindsay correct?

m_a_m_a [10]

Answer:

Yes

Step-by-step explanation:

Let's take any random multiple of 4 as an example:

8 = 2 • 4

64 = 2 • 32

20 = 2 • 10

Try any multiple of 4—this pattern continues.

7 0

3 years ago

Find the perimeter of each of the two non congruent triangles where a=15,b=20 and a=29

Alborosie

Answer:

b. about 63.9 units and 41.0 units

Step-by-step explanation:

In question ∠a= 29° and Side of a= 15 and b= 20

Using sine rule of congruence of triangle.

⇒ $\frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{sin C}$

⇒ $\frac{15}{Sin 29} = \frac{20}{sin B}$

Using value of sin 29°

⇒ $\frac{15}{0.49} = \frac{20}{sin B}$

Cross multiplying both side.

⇒ Sin B= $\frac{20\times 0.49}{15} = 0.65$

∴ B= 41°

Now, we have the degree for ∠B= 41°.

Next, lets find the ∠C

∵ we know the sum total of angle of triangle is 180°

∴∠A+∠B+∠C= 180°

⇒ $29+41+B= 180$

subtracting both side by 70°

∴∠C= 110°

Now, again using the sine rule to find the side of c.

$\frac{b}{SinB} = \frac{c}{SinC}$

⇒ $\frac{20}{sin41} = \frac{C}{sin110}$

Using the value of sine and cross multiplying both side.

⇒ C= $\frac{20\times 0.94}{0.65} = 28.92$

∴ Side C= 28.92.

Now, finding perimeter of angle of triangle

Perimeter of triangle= a+b+c

Perimeter of triangle= $(15+20+28.92)= 63.9$

∴ Perimeter of triangle= 63.9 units

7 0

3 years ago

Solving equations (algebra). Thank you!

LenKa [72]

Answer:

$\large\boxed{\dfrac{1}{x^2}+x^2=23}$

Step-by-step explanation:

$\left(\dfrac{1}{x}+x\right)^2=25\qquad\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\\left(\dfrac{1}{x}\right)^2+2(x\!\!\!\!\diagup)\left(\dfrac{1}{x\!\!\!\!\diagup}\right)+x^2=25\\\\\dfrac{1}{x^2}+2+x^2=25\qquad\text{subtract 2 from both sides}\\\\\dfrac{1}{x^2}+x^2=23$

5 0

3 years ago

Can some one answer this?

timofeeve [1]

9514 1404 393

Answer:

Step-by-step explanation:

A graph shows the zeros are -5, -3, 0, 2. Of these, only 2 is on your list.

2 is a zero of the expression

4 0

3 years ago