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Fittoniya [83]
3 years ago
7

Plz answer this thank you if you do anwser

Mathematics
2 answers:
8090 [49]3 years ago
6 0
The answer is y= m x + c
ELEN [110]3 years ago
4 0
-9x+8 is the answer.
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A gallon of gasoline costs $2.96. Your car has a 25-gallon gas tank and can travel 28.8 miles on each gallon of gasoline. You ta
Andreas93 [3]

Answer:

$70.56

Step-by-step explanation:

Lets convert the mixed number (trip length) to decimal.

We know 3/5 (by long division) is 0.6, so 705  3/5th = 705.60 miles

Now, let's come to the problem:

1 gallon = 28.8 miles (mileage)

or

$2.96 = 28.8 miles

To find cost per mile, we divide:

\frac{2.96}{28.8}=0.10

That means, it costs $0.10 per mile

Since we want to travel 705.60 miles, we multiply to find the cost:

$0.10 per mile * 705.60 miles = $70.56

6 0
4 years ago
Without calculating, would 0.4 + (2 + 0.6) be less than, greater than, or equal to 3? Explain.
Anton [14]

wqual because you round 0.6 to 1 and 0.4 to 0 so 2+1 is 3
4 0
3 years ago
Read 2 more answers
3. Suppose (4, 19) is on the graph of y=f(x). Which of the following points lies on the graph of the transformed function y=f(1/
Leno4ka [110]

Answer:

it is c for shore i got it right

4 0
2 years ago
Help me answer this and explain it please! :)
Fynjy0 [20]

Answer:

90. 04987916

Step-by-step explanation:

Let HI be a

and GH be c

and GI be b

and <GHI be B

Using the law of Cosines,

b^2= -2ac cos (B) + c^2 + a^2

= -2(42)(60) cos (123)+60^2+42^2

= -5040 cos (123) +3600+1764

= -5040(-0. 544639035) +5364

= 2744. 980736+5364

b^2= 8108. 980736

b= Sqrt ( 8108. 980736)

b= 90. 04987916

7 0
3 years ago
Read 2 more answers
Write the expression as an equivalent algebraic expression involving only x.
Kitty [74]

The given expression is \cos \left(2 \cos ^{-1} x\right)

We need to determine the expression as an equivalent algebraic expression involving only x.

The expression \cos \left(2 \cos ^{-1} x\right) has to be expressed as an algebraic expression in x.

Thus, we have;

\cos \left(2 \cos ^{-1} x\right)

Using the identity cos \ (2x)=2cos^2x-1 in the above expression, we get;

\cos \left(2 \cos ^{-1} x\right)=2\ cos^2(cos^{-1}x)-1

Simplifying, we get;

\cos \left(2 \cos ^{-1} x\right)=2[cos(cos^{-1}x)]^2-1

\cos \left(2 \cos ^{-1} x\right)=2(x)^2-1

\cos \left(2 \cos ^{-1} x\right)=2x^2-1

Hence, the expression \cos \left(2 \cos ^{-1} x\right) can be written as 2x^2-1

7 0
4 years ago
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