(-4,0) (-3,3) (-1,0) (0,-3) (1,-5) (3,0)
So, domain numbers are -4, -3, -1, 0, 1, 3
Range are 0, 3, -3,-5,
Just take the ordered pairs and the Xs is the domain and the Ys are the range
Answer:
![Pr = \frac{1}{870}](https://tex.z-dn.net/?f=Pr%20%3D%20%5Cfrac%7B1%7D%7B870%7D)
Step-by-step explanation:
Given
![n =30](https://tex.z-dn.net/?f=n%20%3D30)
Required
Probability of selecting 2 toys of different types
From the question, we understand that all toys are different i.e. 1 of each type.
And the selection is without replacement;
So, after the first toy is selected; there are n - 1 toys left.
So, the probability is:
![Pr = \frac{1}{n} * \frac{1}{n - 1}](https://tex.z-dn.net/?f=Pr%20%3D%20%5Cfrac%7B1%7D%7Bn%7D%20%2A%20%5Cfrac%7B1%7D%7Bn%20-%201%7D)
Substitute ![n =30](https://tex.z-dn.net/?f=n%20%3D30)
![Pr = \frac{1}{30} * \frac{1}{30- 1}](https://tex.z-dn.net/?f=Pr%20%3D%20%5Cfrac%7B1%7D%7B30%7D%20%2A%20%5Cfrac%7B1%7D%7B30-%201%7D)
![Pr = \frac{1}{30} * \frac{1}{29}](https://tex.z-dn.net/?f=Pr%20%3D%20%5Cfrac%7B1%7D%7B30%7D%20%2A%20%5Cfrac%7B1%7D%7B29%7D)
![Pr = \frac{1}{30*29}](https://tex.z-dn.net/?f=Pr%20%3D%20%5Cfrac%7B1%7D%7B30%2A29%7D)
![Pr = \frac{1}{870}](https://tex.z-dn.net/?f=Pr%20%3D%20%5Cfrac%7B1%7D%7B870%7D)
Answer:
a rotation of 180° about point (0.5, -0.5) followed by a dilation of 0.5
Step-by-step explanation:
It would be option number 3 and option number 4