V(cylinder)= πr²h
d=2r,
d is diameter, r is radius.
When diameter is tripled, a new diameter D=3d,
new radius R=3d/2=(3*2r)/2=3r
R=3r
V(new cylinder)= πR²h = π(3r)²h=9πr²h
V(new cylinder)/V(cylinder)=9πr²h/πr²h=9
Volume new cylinder 9 times more the volume of old cylinder.
Let x and y be the numbers;
We have x + 2y = 9 and 2x + y = 21;
Then, x = 9 - 2y;
Finally, 2(9-2y) + y = 21 ;
18 - 4y + y = 21;
18 - 3y = 21;
-3y = 3;
y = - 1;
x = 9 - 2× (-1);
x = 9 + 2 ;
x = 11;
Answer:
Area pf the regular pentagon is 193
to the nearest whole number
Step-by-step explanation:
In this question, we are tasked with calculating the area of a regular pentagon, given the apothem and the perimeter
Mathematically, the area of a regular pentagon given the apothem and the perimeter can be calculated using the formula below;
Area of regular pentagon = 1/2 × apothem × perimeter
From the question, we can identify that the value of the apothem is 7.3 inches, while the value of the perimeter is 53 inches
We plug these values into the equation above to get;
Area = 1/2 × 7.3× 53 = 386.9/2 = 193.45 which is 193 to the nearest whole number
To isolate the variable you would divide both sides of the equation by 3, resulting in the equation to answer c = 4/3 or c = 1.3
Answer:
6 5/12
Step-by-step explanation:
Given the expression :
4 2/3 + 1 3/4
The sum of the numbers :
4 2/3 + 1 3/4
14/3 + 7/4
L.C.M of 3 and 4 = 12
(56 + 21) / 12
77 / 12
= 6 5/12
