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Usimov [2.4K]
3 years ago
7

Circle the integer(s) that have an absolute value of 11

Mathematics
1 answer:
erik [133]3 years ago
3 0

Answer: shouldn't it be -11?

Step-by-step explanation:

im p sure to find the AV its just like the positive version of a number. Kinda rusty since i did this a long time ago lol

You might be interested in
1/x + 1/3x =6 how do you solve this equation for x
Elodia [21]

Answer:

x = 2/9 (or = 0.222)

Step-by-step explanation:

1/x + 1/(3x) =6  (multiply both sides by 3x)

(1/x) (3x)  + [1/(3x)](3x) =6 (3x)

3 + 1 = 18x

4 = 18x

x = 4/18

x = 2/9 (or = 0.222)

3 0
3 years ago
The graph shows a probability distribution. What is P(X<5)
Thepotemich [5.8K]

Answer:

P(x < 5) = 0.70

Step-by-step explanation:

Note:  The area under a probability "curve" must be = to 1.

Finding the sub-area representing x < 5 immediately yields the desired probability.

Draw a dashed, vertical line through x = 5.  The resulting area, on the left, is a trapezoid.  The area of a trapezoid is equal to:

 (average length)·(width, which here is:

  2 + 5

----------- · 0.02  =  (7/2)(0.2) =  0.70

      2

Thus, P(x < 5) = 0.70

7 0
3 years ago
I need to simplify it
aivan3 [116]
3a^2 B^3 C^-2 OVER a^-3 b^6 c^3
7 0
3 years ago
(-y+5•3)+7.2y-9)=6.2y+n
kramer
(-y+5x3)+(7.2y-9)=6.2y+n
(-y+15)+(7.2y-9)=6.2y+n
since you're adding the two parentheses, you don't need to have them there
-y+15+7.2y-9=6.2y+n
7.2y-y +15-9 =6.2y+n
6.2y + 6 =6.2y+n
6.2y - 6.2y -n = -6
-n=-6
n=6

3 0
3 years ago
Help please! (no one was answering it in physics and i really need help)
aivan3 [116]

Let v_0 be the cat's speed just as it leaves the edge of the table. Then taking the point 1.3 m below the edge of the table to be the origin, the cat's horizontal position at time t is given by

x(t)=v_0t

and its height is

y(t)=1.3\,\mathrm m-gt^2

where g is 9.8 m/s^2, the magnitude of the acceleration due to gravity.

The time it takes for the cat to hit the ground is t with

0=1.3\,\mathrm m-gt^2\implies t=\sqrt{\dfrac{1.3\,\rm m}g}\approx0.36\,\mathrm s

(Unfortunately, this doesn't match any of the given options...)

The cat lands 0.75 m away (horizontally) from the edge of the table, so that its speed v_0 was

0.75\,\mathrm m=v_0(0.36\,\mathrm s)\implies v_0\approx2.08\dfrac{\rm m}{\rm s}

(Again, not one of the answer choices...)

I'm guessing there's either a typo in the question or answers.

6 0
3 years ago
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