Pleas help me please and than you! (6th grade math)

Mathematics

1 answer:

klasskru [66]3 years ago

6 0

Answer:

wow u call that 6th grade

Step-by-step explanation:

I am in 8th grade and dont get this at all.

never touched the topic

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A class contains 6 students with black hair, 8 with brown hair, 4 with blonde hair, and 2 with red hair.

kobusy [5.1K]

Answer:

Step-by-step explanation:

If this class contains these types of hair color THEN the class will have

3/10 kids with black hair

1/10 kids have red hair

2/5 kids have brown hair

1/5 kids have blonde hair

_________________________

In total the class has 20 kids

3 0

3 years ago

2) 1.) 3x+3y 6 2x+2y=4

katrin [286]

Answer:

y este egal cu 1

x este egal cu un

Step-by-step explanation:

2 plus 2 egal cu patru( adica 2 ori unu plus 2 ori 1)

La fel si la cea cu 3.

Sper că te am ajutat!!!

8 0

3 years ago

Read 2 more answers

True or false A chance event with probability 1 is certain to happen

Gnesinka [82]

Answer:

True, since 1 is 1/1, which is 100%

Hope that helps! :)

Step-by-step explanation:

7 0

3 years ago

20 POINTS!!!

notka56 [123]

$\dfrac{2}{\sqrt3\cos x+\sin x}=\sec\left(\dfrac{\pi}{6}-x\right)\\\\\dfrac{2}{\sqrt3\cos x+\sin x}=\dfrac{1}{\cos\left(\dfrac{\pi}{6}-x\right)}\ \ \ \ \ (*)\\----------------\\\\\cos\left(\dfrac{\pi}{6}-x\right)\ \ \ \ |\text{use}\ \cos(x-y)=\cos x\cos y+\sin x\sin y\\\\=\cos\dfrac{\pi}{6}\cos x+\sin\dfrac{\pi}{6}\sin x=\dfrac{\sqrt3}{2}\cos x+\dfrac{1}{2}\sin x=\dfrac{\sqrt3\cos x+\sin x}{2}\\------------------------------$

$(*)\\R_s=\sec\left(\dfrac{\pi}{6}-x\right)=\dfrac{1}{\cos\left(\dfrac{\pi}{6}-x\right)}=\dfrac{1}{\dfrac{\sqrt3\cos x+\sin x}{2}}\\\\=\dfrac{2}{\sqrt3\cos x+\sin x}=L_s$