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3 years ago

HELP I NEED HELP ASAP

Mathematics

1 answer:

Ber [7]3 years ago

5 0

Answer:

Step-by-step explanation:

If you figure out the median you'll see that for 8th grafe its 21 and 7th 25 therefore 4 points higher

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Which of the following names the figure in the diagram below?

Greeley [361]

Answer:

pyramid

Step-by-step explanation:

4 0

3 years ago

32% as a fraction in lowest terms

TiliK225 [7]

32% means 32/100

32/100 = 16/50 = 8/25, which is the lowest you can get because you can no longer divide it to get a whole number.

A; 8/25.

3 0

3 years ago

The time it takes a student to walk from the dorm to the chemistry lab follows roughly a Normaldistribution with a mean of 20 mi

creativ13 [48]

Answer:

95.15%

Step-by-step explanation:

We have that the mean (m) is equal to 20, the standard deviation (sd) 3

They ask us for P (x <25)

For this, the first thing is to calculate z, which is given by the following equation:

z = (x - m) / sd

We have all these values, replacing we have:

z = (25 - 20) / (3)

z = 1.66

With the normal distribution table (attached), we have that at that value, the probability is:

P (z <1.66) = 0.9515

Which means that the probability that it arrives before 25 minutes is 95.15%

6 0

3 years ago

18. A child is flying a kite and has let out all

kolbaska11 [484]

Answer:

I'm pretty sure the answer is 45 ft

Step-by-step explanation:

The string is out at all 80 feet, and is 35 feet away from a stop sign. Then wouldn't 80-35=45?

5 0

3 years ago

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

3 years ago