Using Angle Relationships to Solve Equations

IrinaK [193]

Answer:

As per dot plots we see the distribution of prices is close but majority of prices are concentrated in different zones. So MAD would be more similar by the look.

<u>Let's verify</u>

<h3>Neighborhood 1</h3>

55, 55, 60, 60, 70, 80, 80, 80, 90, 120

(55*2+ 60*2+ 70+ 80*3 + 90+ 120)/10 = 75

(20*2+15*2+5+5*3+15+45)/10 = 15

<h3>Neighborhood 2</h3>

100, 110, 110, 110, 120, 120, 120, 140, 150, 160

(100 + 110*3+ 120*3+ 140 + 150+ 160)/10 = 124

(24+14*3+4*3+16*3+16+26+36)/10 = 20.4

As we see the means are too different (75 vs 124) than MADs (15 vs 20.4).

7 0

3 years ago

Read 2 more answers

PLEASE HELP WILL GIVE BRAINLIEST

seropon [69]

Answer:

-6(3x +2) = 2x -5 -20x -7 (use the distributive property )

-18x -12 = -18x - 12 (i combined like terms on the right side of the equation)

at this point I can tell that it's true for any value of x, so they all apply

Step-by-step explanation:

8 0

3 years ago

The support of a wood table are in the shape of a right triangle. Find the third angle of the triangle of the measure of one of

Semenov [28]

<h3>The measure of third angle of triangle is 67 degrees</h3>

<em><u>Solution:</u></em>

Given that,

The support of a wood table are in the shape of a right triangle

Since it is a right angle, one of the angle must be $90^{\circ}$

The measure of one of the angles is 23 degrees

To find: third angle angle

We know that,

Sum of all angles in triangle equals 180 degrees

Therefore,

$90^{\circ} + 23^{\circ} + \text{ third angle } = 180^{\circ}\\\\ \text{ third angle } + 113 = 180\\\\ \text{ third angle } = 180 - 113\\\\ \text{ third angle } = 67^{\circ}$

Thus measure of third angle of triangle is 67 degrees

5 0

3 years ago

please do the steps Solve for d: 1/6d-8=5/8 2. Solve for x: 3x-4+5x=10-2z 3. Solve for c: 7(c-3)=14 4. Solve for m: 11(m/22+3/44

xeze [42]

Answer:

d = 55.5

x = 1

c = 11

m = $\frac{1}{122}$

k = $\frac{a}{(c + 5)}$

Step-by-step explanation:

Sorry, the formatting is slightly hard to understand, but I think this is what you meant.

Q1.

$\frac{1}{6}$ d - 8 = $\frac{5}{8}$ x 2

Step 1. Simplify.

$\frac{5}{8}$ x 2 = $\frac{5}{8}$ x $\frac{2}{1}$ = $\frac{10}{8}$

Step 2. Cancel out the negative 8.

$\frac{1}{6}$ d - 8 = $\frac{10}{8}$

+ 8 to both sides (do the opposite: $\frac{1}{6}$ d is subtracting 8 right now, but to cancel that out, we will do the opposite of subtraction, i.e. addition)

$\frac{1}{6}$ d = $\frac{10}{8}$ + 8

Step 3. Simplify.

$\frac{10}{8}$ + 8 = $\frac{10}{8}$ + $\frac{8}{1}$ = $\frac{10}{8}$ + $\frac{64}{8}$ = $\frac{74}{8}$ = $\frac{37}{4}$

Step 4. Cancel out the $\frac{1}{6}$ .

$\frac{1}{6}$ d = $\frac{37}{4}$

÷ $\frac{1}{6}$ from both sides (do the opposite: d is multiplied by $\frac{1}{6}$ right now, but to cancel that out, we will do the opposite of multiplication, i.e. division)

÷ $\frac{1}{6}$ = x 6

So....

x 6 to both sides

d = $\frac{37}{4}$ x 6 = $\frac{37}{4}$ x $\frac{6}{1}$ = $\frac{222}{4}$ = $\frac{111}{2}$ = 55.5

Step 5. Write down your answer.

d = 55.5

Q2.

3x - 4 + 5x = 10 - 2x × 3

Step 1. Simplify

3x - 4 + 5x = 3x + 5x - 4 = 8x - 4

10 - 2x × 3 = 10 - (2x × 3) = 10 - 6x

Step 2. Cancel out the negative 6x

8x - 4 = 10 - 6x

+ 6x to both sides (do the opposite - you're probably tired of reading this now - right now it's 10 subtract 6x, but the opposite of subtraction is addition)

14x - 4 = 10

Step 3. Cancel out the negative 4

14x - 4 = 10

+ 4 to both sides (right now it's 14x subtract 4, but the opposite of subtraction is addition)

14x = 14

Step 4. Divide by 14

14x = 14

÷ 14 from both sides (out of the [14 × x] we only want the [x], so we cancel out the [× 14])

x = 1

Step 5. Write down your answer.

x = 1

Q3.

7(c - 3) = 14 × 4

Step 1. Expand the brackets

7(c - 3) = (7 x c) - (7 x 3) = 7c - 21

Step 2. Simplify

14 x 4 = 56

Step 3. Cancel out the negative 21

7c - 21 = 56

+ 21

7c = 56 + 21

7c = 77

Step 4. Cancel out the ×7

7c = 77

÷ 7

c = 77 ÷ 7

c = 11

Step 5. Write down your answer.

c = 11

Q4.

11( $\frac{m}{22}$ + $\frac{3}{44}$ ) = 87m + m × 5

Step 1. Expand the brackets

11( $\frac{m}{22}$ + $\frac{3}{44}$ ) = (11 x $\frac{m}{22}$ ) + (11 x $\frac{3}{44}$ ) = ( $\frac{11}{1}$ x $\frac{m}{22}$ ) + ( $\frac{11}{1}$ x $\frac{3}{44}$ ) = $\frac{11m}{22}$ + $\frac{33}{44}$ = $\frac{m}{2}$ + $\frac{3}{4}$