Answer:
50%
Explanation:
According to this question involving a gene coding for seed shape in pea plant, the allele for round seeds (R) is dominant to the allele for wrinkled seeds (r). This means that a heterozygous pea plant (Rr) will have a round seed shape.
If a plant that is heterozygous for seed type (Rr) is crossed with one that has only homzygous wrinkled seeds (rr), the following gametes will be produced by each parent plant:
Rr - R and r
rr - r and r
Using these gametes in a punnet square (see attached image), the following proportions of offsprings will be produced:
Rr, Rr, rr and rr
Rr = round seed offsprings
rr = wrinkled seed offsprings
Since 1 out of 2 offsprings has wrinkled seeds, 1/2 × 100 = 50% is the percentage of offsprings expected to have wrinkled seeds.
<span>C)diffusion. hope it helps u</span>
Answer:
Average speed = total distance / total time
= 68 / 1 5/12 [ change 1 5/12 to an improper fraction - 17/12]
= 68 / 17/12 [perform division]
= 68 * 12/17
= 48 miles per hour
Answer:
Frequency of recessive allele 
Explanation:
Given -
Total Population size = 919
Number of individual with recessive genotype = 341
Frequency of recessive genotype
Frequency of recessive allele 
Hence, option C is correct
This particular area of genetics can be quite complex. So basically in DNA their is adenine, cytosine, guanine, thymine. So, then there is another step to this: Adenine links with Thymine (A is to T), and Cytosine pairs up with Guanine (C is to G). This is known as base pairing. However, when translating DNA to RNA their is a catch, there is no thymine in RNA. Instead there is Uracil. SO in RNA it would be like so: A is to U and C is to G. So when transcribing DNA to mRNA it would be like this. I will give an example: DNA: TGA GTC AAT GGC. However with RNA it would be like this, using the same example I just showed you: ACU CAG UUA CCG. Do you see I it now? Basically when transcribing to RNA you use the opposite of all of the original copy except use Uracil instead of Thmine.
