X^3-3x^2=0 Write in quadratic form

SOMEONE HELP ME WITH THIS

Alexandra [31]

Answer:

X=7 and y=6

Step-by-step explanation:

Y=-2x + 20.......eq(i)

6x-5y=12.....eq(ii)

Now, putting y= - 2x +20 in eq (ii)

6x - 5(-2x + 20)=12

6x + 10x - 100 = 12

16x=12+100

X=112 /16

X=7

Then, putting x=7 in eq (i)

Y=-2*7 +20

=-14 +20

=6

8 0

3 years ago

HELP ME PLEASE!!

LUCKY_DIMON [66]

Using a system of equation, we have that:

a)

x, which is the cost of on-site service.
y, which is the cost of at-store service.
z, which is the cost of by-mail service.

b)

The system is:

$x = 3y$

$z = y - 10$

$15x + 40y + 5z = 3100$

c)

The cost of one on-site repair service is of $90.

Item a:

The variables are:

x, which is the cost of on-site service.
y, which is the cost of at-store service.
z, which is the cost of by-mail service.

Item b:

On-site service costs 3 times as much as at-store service, thus:

$x = 3y$

By mail service costs $10 less than at-store service, thus:

$z = y - 10$

Last week, the shop completed 15 services on-site, 40 services at-store, and 5 services by mail for total sales of $3100, thus:

$15x + 40y + 5z = 3100$

The system is:

$x = 3y$

$z = y - 10$

$15x + 40y + 5z = 3100$

Item c:

The cost of one on-site repair service is x.
First, replacing the first two equations into the third, we find y, and then with it we find x.

$15x + 40y + 5z = 3100$

$15(4y) + 40y + 5(y - 10) = 3100$

$60y + 40y + 5y = 3150$

$105y = 3150$

$y = \frac{3150}{105}$

$y = 30$

Then

$x = 3y = 3(30) = 90$

The cost of one on-site repair service is of $90.

A similar problem is given at brainly.com/question/24823220

3 0

3 years ago

A square has a side of 6.25 feet. What is the area in square feet? Round to the correct significant digits.

denis23 [38]

Area of a square = side^2
area = 6.25^2 = 39.0625 square feet

= 39.06 (rounded)

4 0

3 years ago

A pound of rice crackers costs $2.88. Matthew purchased 1/4 pound of crackers. How much did he pay for crackers?

Rom4ik [11]

He payed 0.72
First you take 2.88, then you multiply it by 1/4 or a simpler way would be to divide 2.88 by 4. The answer is $0.72

6 0

3 years ago

Read 2 more answers

Slav-nsk [51]

Let k be the scale factor relating two similar prisms $P_{1}$ and $P_{2}$ , such that for corresponding parts of prisms $P_{1}$ and $P_{2}$ (for heights, in particular) we have $k= \frac{height\ of \ P_{1} }{height \ of\ P_{2} }$ . In our case $k= \frac{4}{10} = \frac{2}{5}$ .
For surfaces area we have $\frac{Surface \ area \ of \ P_{1} }{Surface \ area \ of \ P_{2}} = k^{2} =( \frac{2}{5} )^{2}= \frac{4}{25}$ .
So, the right answer is 4:25 (choice B)

4 0

3 years ago