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ivann1987 [24]
3 years ago
10

Two students, Jennifer and Jamal, factored the trinomial 6x2 − 3x − 9. Jamal factored it as 3(2x − 3)(x + 1) and Jennifer factor

ed it as (2x − 3)(3x + 3). Indicate which student factored the trinomial completely and which student did not, and explain why.
Mathematics
2 answers:
GaryK [48]3 years ago
7 0
Jamal factored it completely.

in Jennifer's answer, 3x+3 has a common factor of 3 which can be factored to become 3(x+1) which is what Jamal did.
vaieri [72.5K]3 years ago
3 0

no thats wrong Jamal factored it correctly

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Solve. <br> | 3x + 1 | = 2
qwelly [4]
Since this is an absolute value equation, it will have two answers. For the first answer, take away the absolute value bars and solve 3x + 1 = 2. Subtract 1 from both sides to get 3x = 1 and divide each side by 3 to get x = 1/3. Now onto the second solution. This time, take away the absolute value bars and make the other side of the equation, the 2, negative, to get 3x + 1 = -2. Now solve this by subtracting 1 from each side to get 3x = -3 and divide each side to get the other answer which is x = -1. The answer is x = -1 or 1/3, hope this helps!
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What is the difference between a relation and function? Classify each of the following as a function, or not a function. State t
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Answer:

A relation is a subset of cartesian product of two non empty sets whereas A function is a type of relation in which every element of first set has one and only image in the second set.

In a relation an element of the first set can have many images in the second set whereas in a function the first element can have only one image in the second set.

The given relation is not a function as the element 1 is related to 3 different elements in the second set.

Domain={1}

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2 years ago
A quadrilateral is dilated by a scale factor of 2. It's original side measures are 7, 14, 21, and 28.
algol13

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14,28,42 and 56

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Answer: the first one is the answer I think

Step-by-step explanation:

6 0
2 years ago
Can you please help me out
Taya2010 [7]

The bag contains,

Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,

Total marbles (possible outcome) is,

\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}

Let P(R) represent the probablity of picking a red marble,

P(G) represent the probability of picking a green marble and,

P(B) represent the probability of picking a blue marble.

Probability , P, is,

\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}

Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,

That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}

Hence, the best option is G.

5 0
1 year ago
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