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DochEvi [55]
3 years ago
5

For a particular​ event, 669 tickets were sold for a total of ​$4293. If students paid ​$5 per ticket and nonstudents paid ​$8 p

er​ ticket, how many student tickets were​ sold?
Mathematics
1 answer:
solong [7]3 years ago
5 0

Answer:

353 tickets.

Step-by-step explanation:

Let's say that there are s student tickets and n nonstudent tickets.

s + n = 669

5s + 8n = 4293

Multiply -5 by the entire first equation to get...

-5s - 5n = -3345

Combine the two equations.

5s - 5s + 8n - 5n = 4293 - 3345

3n = 948

n = 316

Now, put the number of nonstudent tickets sold back into the first equation.

s + 316 = 669

s = 353 tickets.

Hope this helps!

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Since \arcsin\left(\dfrac{5}{6}\right)\approx 56^{\circ}\approx \dfrac{\pi }{3.2},

four smallest positive solutions are

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3. \dfrac{5}{3.2}+10\approx 11.568,\ k=2;

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An elevator is rated to safely hold ten 250 lb people. The elevator is loaded as follows: three 600 lbs cartons of books, Jim (1
iris [78.8K]
To do this, we will need to find how much the elevator can hold in all. Multiply 10 by 250 to get 2500. Since it can also hold 10% more, multiply 2500 and 0.10 to find out how much 10% is. You get 250. Add 2500 and 250 to get how much the elevator can safely hold. It would be 2750.

To find out how much more weight can be added, first find out how much weight is on the elevator collectively. (books) 600+ (Jim) 180+ (Gavin) 330 + (Deb) 250 + (Susan) 120 = 1480. Subtract this from the amount the elevator can hold, and you get how much more weight can be added. 2750-1480= 1270.

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Answer:

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