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DochEvi [55]
3 years ago
5

For a particular​ event, 669 tickets were sold for a total of ​$4293. If students paid ​$5 per ticket and nonstudents paid ​$8 p

er​ ticket, how many student tickets were​ sold?
Mathematics
1 answer:
solong [7]3 years ago
5 0

Answer:

353 tickets.

Step-by-step explanation:

Let's say that there are s student tickets and n nonstudent tickets.

s + n = 669

5s + 8n = 4293

Multiply -5 by the entire first equation to get...

-5s - 5n = -3345

Combine the two equations.

5s - 5s + 8n - 5n = 4293 - 3345

3n = 948

n = 316

Now, put the number of nonstudent tickets sold back into the first equation.

s + 316 = 669

s = 353 tickets.

Hope this helps!

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2 years ago
Rajan needs 1 liter of 15% hydrochloric acid solution for an experiment. He checks his storage cabinet, but he only has a 5-lite
Delvig [45]

Answer:

  1. <em>0.75</em><em> liters of 5% hydrochloric acid solution </em>
  2. <em>0.25</em><em> liters of 45% hydrochloric acid solution.</em>

Step-by-step explanation:

Let us assume that, x liters of the 5% hydrochloric acid and y liters of the 45% hydrochloric acid solutions are combined.

As Rajan need total of 1 liter of solution, so

x+y=1

i.e x=1-y --------------------1

As Rajan needs 5% hydrochloric acid and 45% hydrochloric acid to make a 1 liter batch of 15% hydrochloric acid, hence acid content of the mixture of two acids will be same as of the final one, so

0.05x+0.45y=1\times 0.15

i.e 5x+45y=15 -------------2

Putting value of x from equation 1 in equation 2,

\Rightarrow 5(1-y)+45y=15

\Rightarrow 5-5y+45y=15

\Rightarrow 5+40y=15

\Rightarrow 40y=15-5=10

\Rightarrow y=0.25

Putting the value of y in equation 1,

x=1-0.25=0.75

Therefore, Rajan must use 0.75 liters of 5% hydrochloric acid solution and 0.25 liters  of 45% hydrochloric acid solution.

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