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DochEvi [55]
3 years ago
5

For a particular​ event, 669 tickets were sold for a total of ​$4293. If students paid ​$5 per ticket and nonstudents paid ​$8 p

er​ ticket, how many student tickets were​ sold?
Mathematics
1 answer:
solong [7]3 years ago
5 0

Answer:

353 tickets.

Step-by-step explanation:

Let's say that there are s student tickets and n nonstudent tickets.

s + n = 669

5s + 8n = 4293

Multiply -5 by the entire first equation to get...

-5s - 5n = -3345

Combine the two equations.

5s - 5s + 8n - 5n = 4293 - 3345

3n = 948

n = 316

Now, put the number of nonstudent tickets sold back into the first equation.

s + 316 = 669

s = 353 tickets.

Hope this helps!

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Answer:

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Given: Let A be the event that the first die lands on 2 and B be the event that the second die lands on 2.

To find:

P(A), the probability that the first die lands on 2

P(B), the probability that the second die lands on 2

P(A and B): the probability that the first die lands on 2 and the second die lands on 2

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