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ra1l [238]
3 years ago
6

2x - 5y +10x - 2y + 3z

Mathematics
1 answer:
Vesnalui [34]3 years ago
6 0

Answer:

1

2

−

7

+

3

Step-by-step explanation:

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Factor 3(8x-4) <br> Sbshbshsbsh
tangare [24]

Answer:

i think its 24x-12? sorry if it is wrong

7 0
3 years ago
Coconuts were on sale, 5 for $4.45. Pineapples were on sale, 4 for $3.40. Which of the following is true?
melomori [17]

Answer: D

Step-by-step explanation: If you do 4/4.45 you get a number approximate to 89 cents. Answers A and B you can cross of because coconuts are 5 cents more than pineapples

3 0
3 years ago
Read 2 more answers
The stock of Company A lost $2.11 throughout the day and ended at a value of $50.64. By what percentage did the stock decline?
9966 [12]

Answer:

4% decline

Step-by-step explanation:

Starting price = 50.64 + 2.11 = 52.75

2.11/52.75 * 100

= 4% decline

8 0
4 years ago
Suppose that when a transistor of a certain type is subjected to an accelerated life test, the lifetime x (in weeks) has a gamma
elena-14-01-66 [18.8K]

Answer:

a) P(1 \leq X \leq 40)

In order to find this probability we can use excel with the following code:

=GAMMA.DIST(40;5,8,TRUE)-GAMMA.DIST(1,5,8,TRUE)

And we got:

P(1 \leq X \leq 40)=0.560

b) P(X \geq 40)=1-P(X

In order to find this probability we can use excel with the following code:

=1-GAMMA.DIST(40,5,8,TRUE)

And we got:

P(X \geq 40)=1-P(X

Step-by-step explanation:

Previous concepts

The Gamma distribution "is a continuous, positive-only, unimodal distribution that encodes the time required for \alpha events to occur in a Poisson process with mean arrival time of \beta"

Solution to the problem

Let X the random variable that represent the lifetime for transistors

For this case we have the mean and the variance given. And we have defined the mean and variance like this:

\mu = 40 = \alpha \beta  (1)

\sigma^2 =320= \alpha \beta^2  (2)

From this we can solve \alpha and [/tex]\beta[/tex]

From the condition (1) we can solve for \alpha and we got:

\alpha= \frac{40}{\beta}    (3)

And if we replace condition (3) into (2) we got:

320= \frac{40}{\beta} \beta^2 = 40 \beta

And solving for \beta = 8

And now we can use condition (3) to find \alpha

\alpha=\frac{40}{8}=5

So then we have the parameters for the Gamma distribution. On this case X \sim Gamma (\alpha= 5, \beta=8)

Part a

For this case we want this probability:

P(1 \leq X \leq 40)

In order to find this probability we can use excel with the following code:

=GAMMA.DIST(40;5,8,TRUE)-GAMMA.DIST(1,5,8,TRUE)

And we got:

P(1 \leq X \leq 40)=0.560

Part b

For this case we want this probability:

P(X \geq 40)=1-P(X

In order to find this probability we can use excel with the following code:

=1-GAMMA.DIST(40,5,8,TRUE)

And we got:

P(X \geq 40)=1-P(X

6 0
3 years ago
Lin runs 5 laps around a track in 6 minutes.
egoroff_w [7]

it would be a ratio5:6

Step-by-step explanation:

6 0
3 years ago
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