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2 years ago

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A helicopter travels 240 miles every 2 hours. The vehicle travels miles.

1 answer:

S_A_V [24]2 years ago

5 0

is this the whole question because there's nothing to find?

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Find the volume of each ball. use the formula. where v is the volume and r is the radius. record the volume in table A of your s

pochemuha

Answer:

The volume of tennis ball = 38.808 $cm^{3}$ .

Volume of golf ball = 33.523 $cm^{3}$ .

Step-by-step explanation:

Given: The radius of the tennis ball is 2.1cm and the radius of thr golf ball is 2.0cm. the formula is V=4πr(to the 3rd power) /3 .

To find: Volume of tennis ball and golf ball .

Formula used: Volume = $\frac{4 π r^{3} }{3}$ .

pi(π) = $\frac{22}{7}$ .

Explanation : We are given that

Radius of the tennis ball = 2.1 cm

radius of the golf ball =2.0 cm.

We need to find the volume of each ball

So , plugging the given values of radius in above formula

Volume of the tennis = $\frac{4*22(2.1)^{3} }{3*7}$

On simplification we get, volume of tennis ball = 38.808 $cm^{3}$

Volume of the golf ball= $\frac{4*22(2.0)^{3} }{3*7}$

On simplification we get, volume of golf ball = 33.523 $cm^{3}$

Therefore , The volume of tennis ball = 38.808 $cm^{3}$ .

Volume of golf ball = 33.523 $cm^{3}$ .

7 0

2 years ago

Read 2 more answers

A line passes through the point (–2, 7) and has a slope of –5. What is the value of a if the point (a, 2) is also on the line?

Andre45 [30]

To be honest I’m not sure but I believe it’s -7 if there’s anymore information please attach it along with your question

6 0

3 years ago

Read 2 more answers

Find where the function is increasing and decreasing. G(x)=1/x^2 +7

eduard

Inc on (-inf,0)
Dec on (0,inf)

3 0

3 years ago

Write a solution in Interval Notation - (you don't have to help me on all, 1 or 2 is fine c: )

Gemiola [76]

QUESTION 1

The given inequality is

$|m|-2>0$

We group like terms to get,

$|m|>2$

This implies that,

$-m>2$ or $m>2$ .

We simplify the inequality to get,

$m$ or $m>2$ .

We can write this interval notation to get,

$(-\infty,-2)\cup (2,+\infty)$ .

QUESTION 2

$|x-4|-3\:>\:5$ .

We group like terms to get,

$|x-4|\:>\:5+3$ .

$|x-4|\:>\:8$

We split the absolute value sign to get,

$-(x-4)\:>\:8$ or $x-4\:>\:8$

This implies that,

$x-4\:$ or $x-4\:>\:8$

$x\:$ or $x\:>\:8+4$

$x\:$ or $x\:>\:12$

We can write this interval notation to get,

$(-\infty,-4)\cup (12,+\infty)$ .

QUESTION 3

The given inequality is

$|6+9x|\leq 24$

We split the absolute value sign to obtain,

$-(6+9x)\leq 24$ or $(6+9x)\leq 24$

This simplifies to

$6+9x\ge -24$ and $6+9x\leq 24$

$9x\ge -24-6$ and $9x\leq 24-6$

$9x\ge -30$ and $9x\leq 18$

$x\ge -\frac{10}{3}$ and $x\leq 2$

$-\frac{10}{3}\leq x\leq2$

We write this in interval form to get,

$[-\frac{10}{3},2]$

QUESTION 4

The given inequality is

$|1-5a|>29$

We split the absolute value sign to get,

$-(1-5a)>29$ or $1-5a>29$

This simplifies to,

$1-5a\:$ or $1-5a\:>\:29$

This implies that,

$-5a\:$ or $-5a\:>\:29-1$

$-5a\:$ or $-5a\:>\:28$

$a\:>\:6$ or $a\:$

We write this in interval notation to get,

$(-\infty,-\frac{28}{5})\cup (6,+\infty)$

7 0

3 years ago

Choose the correct zeros for the following quadratic function

Contact [7]

I need more information

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3 years ago