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forsale [732]
3 years ago
10

Help with this question please help

Mathematics
1 answer:
levacccp [35]3 years ago
8 0
Slope is 2
Y intercept is 4
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The law f(t) = -t2 + 6t + 15 represents the number of kilometers of congestion, as a function of time, registered in a city. Wit
andrey2020 [161]
Time is -b/2a, which is 3.
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3 0
3 years ago
A population of deer mice consists of 200 individuals and has an r = 0.1. A population of wood rats consists of 100 individuals
Mariulka [41]

Answer:

Population of dice mice after one year = 2000

Population of wood rats after one year = 1000

The population of deer mice is growing faster than the popular of wood rats

Step-by-step explanation:

The expression for population = dN/dt = rN

Upon integration N = rN²/2

Therefore for population N = 200 and r= 0.1

N after one year = (0.1 x 200²)/ 2 = 2000

Therefore for population N = 100 and r= 0.2

N after one year = (0.2 x 100²)/ 2 = 1000

Hence the population of deer mice is growing faster than the popular of wood rats

7 0
3 years ago
Can someone solve question c ?
Vitek1552 [10]
If it finished at 1:33 it would’ve started at 12:30
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3 0
3 years ago
Which statement best describes the function represented by the graph
irina [24]

Answer:

the second one seems right but i could be wrong

Step-by-step explanation:

8 0
4 years ago
Lim x-1 x³-2x²+3x-2/(2x^4-3x+1)
UkoKoshka [18]

Since the limit becomes the undetermined form

\displaystyle \lim_{x\to 1} \dfrac{x^3-2x^2+3x-2}{2x^4-3x+1} \to \dfrac{0}{0}

it means that both polynomials have a root at x=1. So, we can fact both numerator and denominator:

x^3-2x^2+3x-2 = (x-1)(x^2-x+2)

2x^4-3x+1 = (x-1)(2x^3+2x^2+2x-1)

So, the fraction becomes

\dfrac{(x-1)(x^2-x+2)}{(x-1)(2x^3+2x^2+2x-1)} = \dfrac{x^2-x+2}{2x^3+2x^2+2x-1}

Now, as x approaches 1, you have no problems anymore:

\displaystyle \lim_{x\to 1} \dfrac{x^2-x+2}{2x^3+2x^2+2x-1} \to \dfrac{2}{5}

4 0
3 years ago
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