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3 years ago

14

(08.05 MC)

1 answer:

oee [108]3 years ago

5 0

Answer:

x=67

Step-by-step explanation:

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State a true Conclusion

Maru [420]

Then Zela lives in Zee.

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3 years ago

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Can you please explain?

Elina [12.6K]

Okay, so what you need to figure out is that how many years in between 21 1/4 and 37 there are based on the amount the tree grows a year. So, 1 3/4 times 9 is 15.75, and this added to 21 1/4 is 37. This means that it will take the tree 9 years to grow from 21 1/4 ft to 37 ft.

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2 years ago

Write it as a mixed number please

kolezko [41]

Answer:

-549/8 as mixed number

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2 years ago

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Is (1, 6) a solution to this system of equations?<br> 5x + 2y = 17<br> x + 3y = 19<br> yes<br> no

Ulleksa [173]

Answer:
Yes

Explanation:
5x + 2y = 17

We are given the values (1, 6)

Substitute then into the equation

(I put a question mark to basically ask the question “is 5(1) + 2(6) equal to 17?”)

5(1) + 2(6) = 17?
5 + 12 = 17?
Yes!

Hope this helped and made sense :)

5 0

3 years ago

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Pyramid A has a triangular base where each side measures 4 units and a volume of 36 cubic units. Pyramid B has the same height,

omeli [17]

Answer:

The volume of pyramid B is 81 cubic units

Step-by-step explanation:

Given

<u>Pyramid A</u>

$s = 4$ -- base sides

$V = 36$ -- Volume

<u>Pyramid B</u>

$s = 6$ --- base sides

Required

Determine the volume of pyramid B <em>[Missing from the question]</em>

From the question, we understand that both pyramids are equilateral triangular pyramids.

The volume is calculated as:

$V = \frac{1}{3} * B * h$

Where B represents the area of the base equilateral triangle, and it is calculated as:

$B = \frac{1}{2} * s^2 * sin(60)$

Where s represents the side lengths

First, we calculate the height of pyramid A

For Pyramid A, the base area is:

$B = \frac{1}{2} * s^2 * sin(60)$

$B = \frac{1}{2} * 4^2 * \frac{\sqrt 3}{2}$

$B = \frac{1}{2} * 16 * \frac{\sqrt 3}{2}$

$B = 4\sqrt 3$

The height is calculated from:

$V = \frac{1}{3} * B * h$

This gives:

$36 = \frac{1}{3} * 4\sqrt 3 * h$

Make h the subject

$h = \frac{3 * 36}{4\sqrt 3}$

$h = \frac{3 * 9}{\sqrt 3}$

$h = \frac{27}{\sqrt 3}$

To calculate the volume of pyramid B, we make use of:

$V = \frac{1}{3} * B * h$

Since the heights of both pyramids are the same, we can make use of:

$h = \frac{27}{\sqrt 3}$

The base area B, is then calculated as:

$B = \frac{1}{2} * s^2 * sin(60)$

Where

$s = 6$

So:

$B = \frac{1}{2} * 6^2 * sin(60)$

$B = \frac{1}{2} * 36 * \frac{\sqrt 3}{2}$

$B = 9\sqrt 3$

So:

$V = \frac{1}{3} * B * h$

Where

$B = 9\sqrt 3$ and $h = \frac{27}{\sqrt 3}$

$V = \frac{1}{3} * 9\sqrt 3 * \frac{27}{\sqrt 3}$

$V = \frac{1}{3} * 9 * 27$

$V = 81$

6 0

2 years ago

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