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3 years ago

Which equation represents the line with a slope of 5/6 that passes through the point (-2, 1)?

Mathematics

2 answers:

andreyandreev [35.5K]3 years ago

5 0

Answer:

Step-by-step explanation:

Slope m = 5/6

The points (-2,1)

So; y1 = 1 and x1 = -2

The equation is y - y1 = m(x - x1)

y - 1 = 5/6(x + 2)

Multiply each term by 6

6y - 6 = 5(x + 2)

6y - 6 = 5x + 10

6y = 5x + 10 + 6

6y = 5x + 16

- 5x + 6y = 16

Multiplying by minus

5x - 6y = -16

mart [117]3 years ago

3 0

Answer:

5x - 6y = -16

Step-by-step explanation:

5/6 = (y - 1)/(x - 2)

cross multiplying,

5x + 10 = 6y - 6

5x - 6y = -16

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3 years ago

Is y=1/2+2 linear? and how do you know just by looking at the equation?

saul85 [17]

Answer:

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3 years ago

If ab = 8 and a^2+b^2=16, then what is the value of (a+b)^2?

aksik [14]

$ab = 8$ & $a^{2} + b^{2} = 16$ so , $( a+b )^{2} = 32$ .

Step-by-step explanation:

Here we have , ab= 8 & a^2+b^2=16 i.e. $ab = 8$ and $a^{2} + b^{2} = 16$ .

We need to find value of (a+b)^2 i.e. $(a+b)^{2}$ :

It's and identity and we know that $( a+b )^{2} = a^{2} +b^{2} +2ab$

⇒ $( a+b )^{2} = a^{2} +b^{2} +2ab$

⇒ $( a+b )^{2} = (a^{2} +b^{2}) +2(ab)$

⇒ $( a+b )^{2} = (16) +2(8)$

⇒ $( a+b )^{2} = (16) +(16)$

⇒ $( a+b )^{2} = 32$

∴ $ab = 8$ & $a^{2} + b^{2} = 16$ so , $( a+b )^{2} = 32$ .

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Step-by-step explanation:

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3 years ago

3024 divided by 42 with remainder

Evgen [1.6K]

Answer:

72 Remainder: 0

Step-by-step explanation:

3024 / 42 = 72

Remainder of 0!

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1 year ago

Read 2 more answers