The two number are 39 and 13
<em><u>Solution:</u></em>
Let the two numbers be "a" and "b"
Let the larger number be "a" and the smaller number be "b"
<em><u>Given that, sum of two numbers is 52</u></em>
a + b = 52 ---------- eqn 1
<em><u>One number is 3 times as large as the other number</u></em>
Larger number = 3 times smaller number
a = 3b -------- eqn 2
<em><u>Let us solve eqn 1and eqn 2</u></em>
<em><u>Substitute eqn 2 in eqn 1</u></em>
3b + b = 52
4b = 52
b = 13
<em><u>Substitute b = 13 in eqn 2</u></em>
a = 3(13)
a = 39
Thus the two number are 39 and 13
Answer:
C or the 3rd one
Step-by-step explanation:
I think that the answer would be two triangles.
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Step-by-step explanation:
<u>Rewrite log4256=4 in a different form:</u>
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Answer:
Here's a possible example:
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Each piece is linear, so the pieces are continuous by themselves.
We need consider only the point at which the pieces meet (x = 3).

The left-hand limit does not equal ƒ(x), so there is a jump discontinuity at x =3.