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mihalych1998 [28]
3 years ago
11

Select the two values of x that are roots of this equation

Mathematics
2 answers:
Olenka [21]3 years ago
7 0

Answer:

c

Step-by-step explanation:

ohaa [14]3 years ago
7 0

There are two answers to the question...

Answer:

B and C

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1. The coordinates of the vertices of parallelogram RMBS are R(–4, 5), M(1, 4), B(2, –1), and S(–3, 0). Using the diagonals, pro
Whitepunk [10]
First, plot the points. Point R would be somewhere in the second Quadrant, point M would be in the first quadrant 1, point B would be in the fourth quadrant, and point S would be on the negative y-axis. A property of rhombi is that their diagonals are perpendicular. One would need to calculate the slopes of the diagonals and determine whether or not they are perpendicular. Lines are perpendicular if and only if their slopes are opposite reciprocals. Example: 2 and -0.5
Formulas needed:
Slope formula:
\frac{ y_{2}- y_{1}  }{ x_{2} - x_{1} }

The figure would look kinda like this:
      R
                  M
  
          S
                       B
 Diagonals are segment RB and segment SM
So, your slope equations would look like this:
 \frac{-1-5}{2-(-4)}
and
\frac{4-(-3)}{1-0}
Slope of RB= -1
Slope of SM=7
Not a rhombus, slopes aren't perpendicular. But this figure may very well be a parallelogram
7 0
3 years ago
(3x+36)^2<br> can anyone please answer i don’t understand how to do this
pav-90 [236]
Expand the EXPRESSION 
9x^2+216x+1296
7 0
3 years ago
HELPPPP PLEASE!!!!!!!!
babunello [35]

Answer:

False, since x values cannot have more than one y value.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Expanding Logarithmic Expressions In Exercise, use the properties of logarithms to rewrite the expression as a sum, difference,
Leya [2.2K]

Answer:  \dfrac{1}{3}[\ln (x+1)+\ln(x-1)]

Step-by-step explanation:

Properties of logarithm :

  1. \log (ab)= \log a+\log b
  2. \log(\dfrac{a}{b})=\log a-\log b
  3. \log a^n= n\log a

The given expression in terms of Natural log : \ln (x^2 - 1)^{\frac{1}{3}}

This will become \dfrac{1}{3}\ln (x^2 - 1)      [ By using Property (3)]

=\dfrac{1}{3}\ln (x^2-1^2)

=\dfrac{1}{3}\ln ((x+1)(x-1))   [\because a^2-b^2=(a+b)(a-b)]

=\dfrac{1}{3}[\ln (x+1)+\ln(x-1)]   [ By using Property (1)]

Hence, the simplified expression becomes \dfrac{1}{3}[\ln (x+1)+\ln(x-1)] .

5 0
3 years ago
What triangle is called with 2 pairs of parallel sides and 4 right angles
vlada-n [284]

This is impossible for a triangle to have however, your description perfectly matches a square or a rectangle

8 0
4 years ago
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