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mihalych1998 [28]
3 years ago
11

Select the two values of x that are roots of this equation

Mathematics
2 answers:
Olenka [21]3 years ago
7 0

Answer:

c

Step-by-step explanation:

ohaa [14]3 years ago
7 0

There are two answers to the question...

Answer:

B and C

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Solve the system by elimination.<br> -8X – 10y = 20<br> -8x – 6y = -4
In-s [12.5K]

Answer:

(5, - 6 )

Step-by-step explanation:

Given the 2 equations

- 8x - 10y = 20 → (1)

- 8x - 6y = - 4 → (2)

Multiply (2) by - 1

8x + 6y = 4 → (3)

Add (1) and (3) term by term to eliminate the x- term, that is

- 4y = 24 ( divide both sides by - 4 )

y = - 6

Substitute y = - 6 into either of the 2 equations and solve for x

Substituting into (1)

- 8x - 10(- 6) = 20

- 8x + 60 = 20 ( subtract 60 from both sides )

- 8x = - 40 ( divide both sides by - 8 )

x = 5

solution is (5, - 6 )

6 0
3 years ago
Y = -27x + 577, where x represents the number of weeks and y represents the amount of money left in her account. After how many
Illusion [34]
To solve this problem, plugin 145 where the y is located and then solve for x
y = -27x +577
145 = -27x +577
145 -577 = -27x
-432 = -27x
-432/-27 = -27x/-27
16 = x
x = 16
After 16 weeks she will have $145 dollars in her account.

7 0
4 years ago
Two paper drink cups are shaped like cones. The small cone can hold 6 oz of water. The large cone is 4/3 the height and 4/3 the
Ivahew [28]
B is the answer 14 is
6 0
3 years ago
Read 2 more answers
It is known that IQ scores form a normal distribution with a mean of 100 and a standard deviation of 15. If a researcher obtains
sdas [7]

Answer:

X \sim N(100,15)  

Where \mu=100 and \sigma=15

We select a sample of n=16 and we are interested on the distribution of \bar X, since the distribution for X is normal then we can conclude that the distribution for \bar X is also normal and given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Because by definition:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

E(\bar X) = \mu

Var(\bar X) = \frac{\sigma^2}{n}

And for this case we have this:

\mu_{\bar X}= \mu = 100

\sigma_{\bar X} = \frac{15}{\sqrt{16}}= 3.75

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the IQ scores of a population, and for this case we know the distribution for X is given by:

X \sim N(100,15)  

Where \mu=100 and \sigma=15

We select a sample of n=16 and we are interested on the distribution of \bar X, since the distribution for X is normal then we can conclude that the distribution for \bar X is also normal and given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Because by definition:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

E(\bar X) = \mu

Var(\bar X) = \frac{\sigma^2}{n}

And for this case we have this:

\mu_{\bar X}= \mu = 100

\sigma_{\bar X} = \frac{15}{\sqrt{16}}= 3.75

6 0
3 years ago
At Chester’s Bakery, a box of 12 donuts sells for $8.50. What is the unit price of the donuts in the box, rounded to the nearest
adelina 88 [10]
If 12 donuts cost $8.50, you can divide $8.50/12 donuts (presumably with a calculator) to get $0.7083/donut which rounds to $0.71/donut. Make sense?
7 0
3 years ago
Read 2 more answers
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