Answer:
-55. just multiple -5 by 11
Answer:
y + 4 = 2(x - 2)
Step-by-step explanation:
There is an infinite number of possible equation that satisfies this requirement. If the y = -4 when x = 2 in the equation, the point (2, -4) must be a solution to the equation. We can use the point-slope form to create an equation that satisfies this requirement. The point-slope form is:
y - y1 = m(x - x1) where m is the slope and (x1, y1) is a solution to the equation.
We know that (2, -4) must be a solution to the equation that we are trying to make. We can use (2, -4) as our (x1, y1). Since having (2, -4) as a solution is our only requirement, the slope can be any real number. I am going to make my slope 2 (you can choose whatever you want). So:
(x1, y1) = (2, -4)
m = 2
Now plug these into out point-slope equation:
y + 4 = 2(x - 2)
Remember, this is just one of infinitely many equations that meets the requirement.
Happy studying. :)
Hello,
A:
2x²-7x-4=0
==>2x²-8x+x-4=0
==>2x(x-4)+1(x-4)=0
==>(x-4)(2x+1)=0
==>(x=4) or (x=-1/2)
B: where is the sign "=" !!!!!!!!!!!!!!!!!!
81x^-1=(9x²+1)(3x+1)(3x-1) I can not go any further.
C)
2x²-32=0
==>x²-16=0
==>(x+4)(x-4)0
==>x=-4 or x=4
D:
where is the sign "="!!!!!!!!!!!!!!!!!!!!!!!!
x^2-7x+12=(x-4)(x-3) but I can not go ant further....
F(x)=x^2+bx-16
x=5
F(5)=5^2+b(5)-16
=25+5b-16=0
=5b+9=0
=5b=-9
=b= -9/5
By remainder theorem
