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goblinko [34]
3 years ago
12

How do you do the bottom portion of this? It’s my younger sister’s homework . I’m a sophomore and have no idea how to do it!

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
6 0

Hello!

Looking at how you set up the proportion, it is correct.

Although, the multiplication is incorrect.

You are supposed to multiply 68 by 25 which comes out to 1700. Then, you should divide it by 100 to get x = 17.

\frac{x}{25} = \frac{68}{100}

100x = 68 * 25

100x = 1700 (divide both sides by 100)

x=17

Therefore, you should expect Sparky to catch it 17 times.

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Help please only in number 15!!!!!$ thank youuuuuu
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This is the answer...


y=250-25x
y=30+30x
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I’m the parking lot at a truck shop there were 6 more cars than 18-wheel trucks. There are 134 wheels in the parking lot. How ma
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112 wheels were in the parking lot
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Use the rule 2 + 3 to find the missing number on the table.
vfiekz [6]

Answer:

14

Step-by-step explanation:

11 + 3 = 14

Hope it helps!

Thanks!

7 0
3 years ago
Find the volume of a cylinder that has a radius of 6 feet and a height of 10 feet. Use 3.14 for pi
dybincka [34]
V = pi r^2 h
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3 years ago
In a population of similar households, suppose the weekly supermarket expense for a typical household is normally distributed wi
Rina8888 [55]

Answer:

P(Y ≥ 15) = 0.763

Step-by-step explanation:

Given that:

Mean =135

standard deviation = 12

sample size n  = 50

sample mean \overline x = 140

Suppose X is the random variable that follows a normal distribution which represents the weekly supermarket expenses

Then,

X \sim N ( \mu \sigma)

The probability that X is greater than 140 is :

P(X>140) = 1 - P(X ≤ 140)

P(X>140) = 1 - P( \dfrac{X-\mu}{\sigma} \leq \dfrac{140-135}{12})

P(X>140) = 1 - P( \dfrac{X-\mu}{\sigma} \leq \dfrac{5}{12})

P(X>140) = 1 - P( Z\leq0.42)

From z tables,

P(X>140) = 1 - 0.6628

P(X>140) = 0.3372

Similarly, let consider Y to be the variable that follows a binomial distribution of the no of household whose expense is greater than $140

Then;

Y \sim Binomial (np)

Y \sim Binomial (50,0.3372)

∴

P(Y ≥ 15) = 1- P(Y< 15)

P(Y ≥ 15) = 1 - ( P(Y=0) + P(Y=1) + P(Y=2) + ... + P(Y=14) )

P(Y \geq 15) = 1 - \begin {pmatrix} ^{50}_0 \end {pmatrix} (0.3372)^0 (1-0,3372)^{50} + \begin {pmatrix} ^{50}_1 \end {pmatrix} (0.3372)^1 (1-0,3372)^{49}  + \begin {pmatrix} ^{50}_2 \end {pmatrix} (0.3372)^2 (1-0,3372)^{48} +...  + \begin {pmatrix} ^{50}_{50{ \end {pmatrix} (0.3372)^{50} (1-0,3372)^{0}

P(Y ≥ 15) = 0.763

7 0
3 years ago
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