Biodiversity decreases, and the overall health of the ecosystem decreases.
Answer: Option D
<u>Explanation:</u>
In a niche when two different species occupy a niche competition arises between them. In due course both the species fight for existence and nature selects the best adaptable one to win. The other species either reduces in its population or gradually in struggle for existence they deteriorate and die.
Hence a decrease in bio diversity happens here due to natural selection. If the biodiversity is decreased in a particular niche it affects the growth of different species which in turn affect the whole ecosystem resulting in decrease of the overall health in an ecosystem.
Answer:
Sometimes referred to as DNA-DNA hybridization, this process hybridizes the genetic information from two different organisms to determine similarities between them. Scientists separate strands of DNA from both species using heat, which breaks the bonds between the base pairs that link the two sides of the double helix.
Explanation:
Answer:
All made of cells, All have the DNA-->RNA-->Protein method of information transfer(can't think of exact word)
Explanation:
Answer:
Enter your immune systems it can also be in the ffood you eat
Explanation:
Answer:
1. G° = -RT ln (G1P/P)
3.1 = 8.314 × 310 × ln (G1P/P)
3.1 / 2577.34 = ln (G1P/P)
0.0012 = ln (G1P/P)
0.0012 = (log G1P/P)/log 2.71828
0.4342 × 0.0012 = log G1P/P
0.00052 = log G1P/P
G1P/P = 10^0.00052 = 1.0012
P/G1P = 1/1.0012 = 0.9988
2. The cleavage of glycogen phosphorolytically is beneficial for the cell to conduct the process as the discharged glucose is phosphorylated. A general hydrolytic cleavage would give rise to only a glucose, which has to be phosphorylated again with the help of ATP.
Another merit of phosphorylated glucose is that it comprises the negative charge and cannot diffuse out of the muscle cell. Thus, the reaction will not be at equilibrium under the physiological conditions and always encourages the generation of the products. The formation of products will amend the change in free energy in such a manner that the reaction will always carry in the forward direction.
3. Greater the ratio of [Pi]/[glucose-1-phosphate], higher will be the relative rate of glycogen phosphorylase in comparison to the phosphoglucomutase as the transformation of Glu-1-P becomes slow because of lesser accessibility of substrate.
