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MAXImum [283]
2 years ago
8

During a hypoperfusion state in the​ body, what division of the autonomic nervous system is responsible for initiating the negat

ive feedback​ systems?
Biology
1 answer:
Ahat [919]2 years ago
4 0
<h2>Autonomic Nervous System</h2>

Explanation:

  • <em>The body additionally animates the adrenal medulla to discharge epinephrine and norepinephrine into the circulatory system  </em>
  • It is term as "a decresses  amount of blood flow". when ischemia caused because of low blood stream, so called "hypoperfusion".
  • Reasons for hypoperfusion incorporate <em>low circulatory strain, </em>cardiovascular breakdown or loss of blood volume. Ischemia can influence parts of the  body
  • <em>Shock  is another name for hypoperfusion</em>
  • There is regularly a tightening of blood stream going to organs in the body including the mind.
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The solubility of any substance in water depends on its polarity. The polar molecule dissolves more easily in the water than the non polar molecule. Amino acids have different polarity at different pH.

(a) (Lys-Ala)3 : The (Lys-Ala)3 contain more positive charge and highly polar the at pH 7 as compared with the  (Gly)20 that remains uncharged and has less polarity.

(b) (Glu)20 :This amino acids negatively charged at pH 7 and highly polar than the (Phe-Met)3 which is non polar or less polar and hence least soluble  in water.

(c) (Asn-Ser-His)5 is highly polar at pH 3 as compared with the (Ala-Asp-Gly)5 that contains the carboxylate groups of Asp residues that are partially neutral. The  (Asn-Ser-His)5 contains = the imidazole groups of His residues are fully polar and soluble in water.

(d) (Asn-Ser-His)5 is polar at pH 6.0 because both have polar side chains Ser but (Asn-Ser-His)5 is only partially partially protonated due to the His side chains. Thus,  (Asn-Ser-His)5 is more soluble in water.

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After Cytokinesis, the cells return to Interphase

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2 years ago
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Alex_Xolod [135]

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Explanation:

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Cell A is more efficient at exchanging substances due to larger surface area to volume ratio.

Cell A is more efficient at exchanging substances with the surrounding environment than cell B because it has the larger surface-area-to-volume ratio. Larger surface area of the cell exchanges more substances with the surrounding environment while on the other hand, lower surface area of the cell exchanges less materials with the environment so we can conclude that cell A is more efficient at exchanging substances due to larger surface area to volume ratio.

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