Answer:
For the first reaction the reagents are: MgCl2 and Na2CO3
For the second reaction the reagents are: Na2HPO4 and CaCl2
Explanation:
Precipitation reactions lie in the production of a compound that is not soluble, which is called a precipitate, this precipitate is produced when two different solutions are combined, each of which will contribute an ion for the formation of the precipitate. In the first reaction you have:
MgCl2 + Na2CO3 = MgCO3 + 2 NaCl
Type of reaction: double displacement
The second reaction is as follows:
4Na2HPO4 + 3CaCl2 → Ca3 (PO4) 2 + 2NaH2PO4 + 6NaCl
It is the reaction of sodium hydrochlorophosphate and calcium chloride
Answer:
I believe it will still be 4.00
Explanation:
The mass of sodium sulfite that was used will be 1,890 grams.
<h3>Stoichiometric problems</h3>
First, the equation of the reaction:

The mole ratio of SO2 produced and sodium sulfite that reacted is 1:1.
Mole of 960 grams SO2 = 960/64 = 15 moles
Equivalent mole of sodium sulfite that reacted = 15 moles
Mass of 15 moles sodium sulfite = 15 x 126 = 1,890 grams
More on stoichiometric problems can be found here: brainly.com/question/14465605
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The Chemical reactivity of metals varies with your eletropositividade, so the more eletropositivo is the most reactive element is metal. The most reactive metals are those that have great tendency to lose electrons and therefore form positive ions with more ease.
hope this helps!
Answer: There are 6 atoms on reactant side and 6 atoms on product side.
Explanation:

As can be seen from the balanced equation the no of atoms i 1 molecule of
is 3, thus 2 molecules contain 6 atoms.
According to law of conservation of mass, in a balanced chemical equation the number of atoms on product side must be equal to the number of atoms on reactant side.
Thus there are 6 atoms formed in
.