Answer:
+1
Explanation:
For the equation to be balanced, the total mass number and the total atomic number on both side of the equation but be equal.
This is illustrated:
For the mass number:
Left side: 22
Right side: 22 + 0 = 22
For the atomic number:
Left side: 11
Right side: 10 + x
11 = 10 + x
Collect like terms
x = 11 - 10
x = 1
See attachment for further explanation.
Selective uptake is the procedure with the aid of using which membranes in cells decide what molecules can cross in and what molecules can exit of a cell.
The studies aimed to expand chemically changed PIM-1s to be used in adsorption and fueloline separation processes. In particular, the nitrile institution in PIM-1 became transformed to numerous one of a kind purposeful organizations to control the interplay capacity of PIM-1 with one of a kind species. Synthesis of PIM-1 became done with the aid of using one of a kind methods, the usage of each the low (72h, 65 °C) and the excessive temperature (forty min, 160 °C) methods.
The response led to a aggregate of hydrolysis products. The composition of the polymer has a profound impact at the very last overall performance of the polymer. Powder samples of hydrolysed PIMs had been used withinside the studies. The discount of nitrile to number one amine became done the usage of borane dimethyl sulphide complex, ensuing in amine PIM-1.
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Answer:
4.6L
Explanation:
Use the equation (P1*V1)/(T1)=(P2*V2)/(T2)
P= pressure
V= volume
T= temperature in kelvins (remember K= C + 273)
Convert atm to mmHg or vise versa
1.5atm*(760mmhg/1atm)= 1140mmHg
(733mmHg * 5.36L)/(298K)=(1140mmHg * V)/(402K)
V= 4.6 or 4.65L (depending on sig figs)
Answer:
There were 0.00735 moles Pb^2+ in the solution
Explanation:
Step 1: Data given
Volume of the KI solution = 73.5 mL = 0.0735 L
Molarity of the KI solution = 0.200 M
Step 2: The balanced equation
2KI + Pb2+ → PbI2 + 2K+
Step 3: Calculate moles KI
moles = Molarity * volume
moles KI = 0.200M * 0.0735L = 0.0147 moles KI
Ste p 4: Calculate moles Pb^2+
For 2 moles KI we need 1 mol Pb^2+ to produce 1 mol PbI2 and 2 moles K+
For 0.0147 moles KI we need 0.0147 / 2 = 0.00735 moles Pb^2+
There were 0.00735 moles Pb^2+ in the solution
It's either B or D because there would be 2 coefficients of hydrogen and one of oxygen
