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Pachacha [2.7K]

3 years ago

14

58,511 divieded by 21 the qoutient is 2,786 r?

1 answer:

Wittaler [7]3 years ago

3 0

Answer:

5

Step-by-step explanation:

The answer is 5 Have fun

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Find the answer to each trigonometric function below.

Airida [17]

Answer:

Sin A = $\frac{opposite}{hypotenuse} =\frac{32}{40} =\frac{4(8)}{5(8)} =\frac{4}{5}$
Cos C = $\frac{adjacent}{hypotenuse} =\frac{16}{34}=\frac{2(8)}{2(17)} =\frac{8}{17}$
Tan A = $\frac{opposite}{adjacent} =\frac{21}{20}$

8 0

3 years ago

I will give Brainiest if your right

Setler79 [48]

Answer:

I'm always right B-) SHEESH

5 0

3 years ago

-1 1/2 _ -1 3/4 which one is greater or less, or equal?

sleet_krkn [62]

Answer:

The answer is -1 1/2 is less than -1 3/4

Step-by-step explanation:

I look at it more as numbers, so for example 1/2 can be simplified into 50, and 3/4 is 75/ 75 would be greater if it was positive. But, with there being a negative 1 in front of the answer, the lowest number closest to 0 is better. :D

8 0

2 years ago

Read 2 more answers

Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant

Viktor [21]

Answer:

Therefore $k= \frac{ln2 }{18}$ , A=184

Step-by-step explanation:

Given function is

$T(t)=230 -e^{-kt}$

where T(t) is the temperature in °C and t is time in minute and A and k are constants.

She noticed that after 18 minutes the temperature of the pie is 138°C

Putting T(t) =138°C and t= 18 minutes

$138=230 -Ae^{-k\times 18}$

$\Rightarrow -Ae^{-18k}=138-230$

$\Rightarrow Ae^{-18k}=92$ .....(1)

Again after 36 minutes it is 184°C

Putting T(t) =184°C and t= 36 minutes

$184=230-Ae^{-k\times 36}$

$\Rightarrow Ae^{-36k}=230-184$

$\Rightarrow Ae^{-36k}=46$ .......(2)

Dividing (2) by (1)

$\frac{Ae^{-36k}}{Ae^{-18k}}=\frac{46}{92}$

$\Rightarrow e^{-18k}=\frac{46}{92}$

Taking ln both sides

$ln e^{-18k}=ln\frac{46}{92}$

$\Rightarrow -18k =ln (\frac12)$

$\Rightarrow -18k= ln1-ln2$

$\Rightarrow k= \frac{ln2 }{18}$

Putting the value k in equation (1)

$Ae^{-18\frac{ln2}{18}}=92$

$\Rightarrow A e^{ln2^{-1}}=92$

$\Rightarrow A.2^{-1}=92$

$\Rightarrow \frac{A}{2}=92$

$\Rightarrow A= 92 \times 2$

⇒A= 184.

Therefore $k= \frac{ln2 }{18}$ , A=184

7 0

3 years ago

The variable z is inversely proportional to x. When x is 16, z has the value 0.9375.

Setler [38]

Since z is inversely proportional to x, when x increases by a factor of 26/16, z will be multiplied by the inverse of that factor: 16/26

$z=\dfrac{16}{26}\cdot 0.9375=0.5\overline{769230}=\dfrac{15}{26}$

6 0

3 years ago