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Evgesh-ka [11]
3 years ago
5

Can somebody please help with this ?? :)

Mathematics
1 answer:
Xelga [282]3 years ago
3 0

Answer:

1/2 pound

1 ounce

17,000 mcg

10grams

0.4

12 mg

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Which number produces a rational number when multiplied by 0.5?
xxMikexx [17]

If the number begins by being rational, multiplying by 0.5 will not change whether or not it is rational. It will remain rational.


That would include any even number 12 * 0.5 = 6

12 started out as rational, so the answer is rational (6)


Any odd number is also rational

23 * 0.5 = 11.5

23 and 11.5 are both rational.


3.636363636 ... is rational so when multiplied by 0.5 the result will be rational.

1.818181818....


So if we start with something irrational like pi

then pi * 0.5 is not rational.

If you have choices, please list them.
4 0
3 years ago
Home Rentals
Fittoniya [83]
It is center point I think
8 0
3 years ago
A researcher plants 22 seedlings. After one month, independent of the other seedlings, each seedling has a probability of 0.08 o
Andrews [41]

Answer:

E(X₁)= 1.76

E(X₂)= 4.18

E(X₃)= 9.24

E(X₄)= 6.82

a. P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= 0.00022

b. P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= 0.000001

c. P(X₁≤2) = 0.7442

Step-by-step explanation:

Hello!

So that you can easily resolve this problem first determine your experiment and it's variables. In this case, you have 22 seedlings (n) planted and observe what happens with the after one month, each seedling independent of the others and has each leads to success for exactly one of four categories with a fixed success probability per category. This is a multinomial experiment so I'll separate them in 4 different variables with the corresponding probability of success for each one of them:

X₁: "The seedling is dead" p₁: 0.08

X₂: "The seedling exhibits slow growth" p₂: 0.19

X₃: "The seedling exhibits medium growth" p₃: 0.42

X₄: "The seedling exhibits strong growth" p₄:0.31

To calculate the expected number for each category (k) you need to use the formula:

E(XE(X_{k}) = n_{k} * p_{k}

So

E(X₁)= n*p₁ = 22*0.08 = 1.76

E(X₂)= n*p₂ = 22*0.19 = 4.18

E(X₃)= n*p₃ = 22*0.42 = 9.24

E(X₄)= n*p₄ = 22*0.31 = 6.82

Next, to calculate each probability you just use the corresponding probability of success of each category:

Formula: P(X₁, X₂,..., Xk) = \frac{n!}{X_{1}!X_{2}!...X_{k}!} * p_{1}^{X_{1}} * p_{2}^{X_{2}} *.....*p_{k}^{X_{k}}

a.

P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= \frac{22!}{3!4!6!} * 0.08^{3} * 0.19^{4} * 0.42^{6}\\ = 0.00022

b.

P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= \frac{22!}{5!5!7!} * 0.08^{5} * 0.19^{5} * 0.31^{7}\\ = 0.000001

c.

P(X₁≤2) = \frac{22!}{0!} * 0.08^{0} * (0.92)^{22} + \frac{22!}{1!} * 0.08^{1} * (0.92)^{21} + \frac{22!}{2!} * 0.08^{2} * (0.92)^{20} = 0.7442

I hope you have a SUPER day!

8 0
3 years ago
The following data values represent a population. What is the variance of the values? 7, 5, 11, 1, 11
MaRussiya [10]
The mean is 35/5=7

The variance is the average of the sum of squared differences of each element from the mean:

v=((7-7)^2+(5-7)^2+(11-7)^2+(1-7)^2+(11-7)^2)/5

v=(0+4+16+36+16)/5

v=14.4
3 0
3 years ago
Read 2 more answers
WhiThree-fifths of the members of the Spanish club are girls. There are a total of 30 girls in the Spanish club.
vesna_86 [32]

Answer:

The total members in the Spanish Club  = 50

Step-by-step explanation:

Let the total members in the Spanish Club = x

Now, number of girls in the club = 30

Three-fifths of the members are girls.

⇒ (\frac{3}{5} )  of total members x  =  30

or, (\frac{3}{5})  \times  x =  30\\

Now, solving for x, we get:

x = 30 \times\frac{5}{3}   = 50

or, x   = 50

Hence,the total members in the Spanish Club  = 50

7 0
3 years ago
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