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Natali5045456 [20]
2 years ago
15

Thank you in advance!

Mathematics
1 answer:
kondaur [170]2 years ago
5 0

Answer:

can you solve my math question check my profile and see tge latest question pls

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krek1111 [17]
WHat grade level are you that would help me to know mark me brainliest for answer
8 0
3 years ago
I don’t understand how to identify quadratic transformations. Can I have so help please?
Levart [38]

Answer:

The parent function for a quadratic is f(x) = x^2. If there is something other than this, that is how you know it is a quadratic transformation.

8 0
2 years ago
Write an equation in standard form of the line that contains the point (-2,4) and is parallel to (has the same slope as) the lin
CaHeK987 [17]

Answer:

The equation of the line in standard form is -8x + y = 20

Step-by-step explanation:

The standard form of the linear equation is Ax + By = C, where

  • A, B, and C are integers

The slope-intercept form of the linear equation is y = m x + b, where

  • m is the slope
  • b is the y-intercept

Parallel lines have equal slopes

∵ The line is parallel to the line y = 8x - 2

→ Compare it with the slope-intercept form above

∴ m = 8

∵ The parallel lines have the same slopes

∴ The slope of the line = 8

→ Substitute it in the slope-intercept form above

∴ y = 8x + b

∵ The line passes through the point (-2, 4)

∴ x = -2 and y = 4

→ Substitute x by -2 and y by 4 in the equation to find b

∵ 4 = 8(-2) + b

∴ 4 = -16 + b

→ Add 16 to both sides

∴ 4 + 16 = -16 + 16 + b

∴ 20 = b

→ Substitute the value of b in the equation above

∴ y = 8x + 20

→ Subtract both sides by 8x

∵ y - 8x = 8x - 8x + 20

∴ y - 8x = 20

→ Switch x and y

∴ -8x + y = 20

∴ The equation of the line in standard form is -8x + y = 20

8 0
3 years ago
Write an equation that represents the line.<br> Use exact numbers.<br> (-2,-1)<br> (4,6)
vazorg [7]

Check the picture below.

to get the equation of any straight line, we simply need two points off of it, so let's use those in the picture

(\stackrel{x_1}{-2}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{6})~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{6}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{(-2)}}} \implies \cfrac{6 -1}{4 +2} \implies \cfrac{ 5 }{ 6 }

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{\cfrac{5}{6}}(x-\stackrel{x_1}{(-2)})\implies y-1=\cfrac{5}{6}(x+2) \\\\\\ y-1=\cfrac{5}{6}x+\cfrac{5}{3}\implies y=\cfrac{5}{6}x+\cfrac{5}{3}+1\implies y=\cfrac{5}{6}x+\cfrac{8}{3}

6 0
1 year ago
CAN SOMEONE PLEASE HELP ME???<br> ↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓∵
nata0808 [166]

Answer:

it is number 3 (-1/5)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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