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barxatty [35]
2 years ago
11

Your employer is trying to select from a list of possible capital projects. The projects, along with their cost and benefits, ar

e listed below. The capital budget available is $1 million. In addition to spending constraints, your employer would like to select at least 2 projects. Projects 2 and 4 cannot both be selected together. Formulate the problem as a linear program and determine the optimal solution.
Project Cost Net Present Value
1 $300,000 $720,000
2 $260,000 $780,000
3 $215,000 $690,000
4 $240,000 $700,000
5 $295,000 $510,000

1. Which projects should be selected?
a. Project 1 will
b. Project 2 will
c. Project 3 will
d. Project 4 will
e. Project 5 will

2. What is the total net present value of these projects?
Business
1 answer:
den301095 [7]2 years ago
8 0

Answer:

Project 1, 2 and 3 will be selected

Total NPV of these projects will be $2,190,000

Explanation:

Availability of capital = 1 million

Minimum 2 projects should be selected

Project 2 and 4 cannot be selected together.

Value of project =  NPV / Cost

P1 = 720,000 / 300,000 = 2.4

P2 = 780,000 / 260,000 = 3

P3 = 690,000 / 215,000 = 3.2

P4 = 700,000 / 240,000 = 2.9

P5 = 510,000 / 295,000 = 1.7

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They’re affordable and highly targeted.
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3 years ago
A certain project has three activities on its critical path. Activity A’s normal completion time is five days. It can be crashed
Snowcat [4.5K]

Answer:

Acitivy B should be crashed first by 2 days and Activity B has a crash cost per days of $25, it will be crashed for a total of $50.

Explanation:

activity A =

normal time (NT) = 5 days

Normal cost (NC) = $0

crash time (CT) = 3 days

Crash cost (CC) = $500

crash cost per day = [CC - NC]/[CT - NT] = $250/day

activity B:

normal time (NT) = 6 days

Normal cost (NC) = $0

crash time (CT) = 4 days

Crash cost (CC) = $50

crash cost per day = [CC - NC]/[CT - NT] = $25/day

activity C:

normal time (NT) = 8 days

Normal cost (NC) = $0

crash time (CT) = 3 days

Crash cost (CC) = $1000

crash cost per day = [CC - NC]/[ CT- NT] = $200/day

The activity that takes the least cost to speed up is the first one to be crashed. from the computations, activity B takes the least cost to speed up, so the project manager should crash activity B first by 2 days.

Therefore, Acitivy B should be crashed first by 2 days and Activity B has a crash cost per days of $25, it will be crashed for a total of $50.

6 0
3 years ago
3. Imagine that you are working at a clothing or grocery store, and answer the questions
Deffense [45]

B. To help determine how much inventory to keep in stock of each item in the outlet, I would consider two factors. The first one is the <u>certain amount of each item type </u>in the first week - determining the number of each items input in the stock to be the original data to compare. The second is the <u>number of items sold and still on stock</u>. This would help determine invetory to keep in stock.

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Pursuing multiple market segments at the same time is the best way to enter new markets. Group of answer choices True False
Archy [21]

It should be noted that pursuing multiple market segments at the same time is not the best way to enter new markets. Therefore, it's false.

<h3>What is a market?</h3>

A market simply means the coming together of a buyer and seller for transactions purpose.

In this case, pursuing multiple market segments at the same time is not the best way to enter new markets. One needs to have complete knowledge before entering a market.

Learn more about market on:

brainly.com/question/25754149

7 0
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Answer:

Natural monopoly

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A natural monopoly refers to a type of monopoly that occurs when the start-up costs or infrastructural costs are high or economies of scale in an industry are very powerful in such a way that only the largest supplier in the industry which is usually the first supplier in the market has a great advantage over potential competitors and therefore becomes the only supplier in the industry.

On the long-run average cost (LRAC) curve, a natural monopoly exists when the quantity demanded is less than the minimum quantity that is required to be at the bottom of the LRAC curve.

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