Let the value of the car be represented by V and the amount of years by y.
This gives us the following formula:
V = 25,635 - 3000y
(This is because we start with a value of $25,635 and the value decreases by $3,000 every year 'y')
Now, we want to know when the car is worth $3,135, so we know V = 3,135
Now we can make up our equation:
25,365 - 3,000y = 3,135
Collecting terms gives us:
-3,000y = -22,500
Finally we divide by -3,000 to find 'y'
y = -22,500 / -3,000 = 7.5
Hence, the car will be worth $3,135 after 7.5 years.
Your answer would be 3.4
Anything under 5 it stays the same and anything over 5 it goes up one
Answer: (4-4i)+(3-2i) = 7-6i
Step-by-step explanation:
To add or subtract two complex numbers, just add or subtract the corresponding real and imaginary parts. For instance, the sum of 4 -4i and 3 - 2i is 7 -6i. The numbers in standard form will be a + bi, where a is the real part and bi is the imaginary part.
Answer:
g(-1) = 6
g(0) = 5
g(1) = 6
g(2) = 9
Step-by-step explanation:
Step 1: Plug in -1 for <em>x</em>
g(-1) = (-1)² + 5
g(-1) = 1 + 5
g(-1) = 6
Step 2: Plug in 0 for <em>x</em>
g(0) = 0² + 5
g(0) = 0 + 5
g(0) = 5
Step 3: Plug in 1 for <em>x</em>
g(1) = 1² + 5
g(1) = 1 + 5
g(1) = 6
Step 4: Plug in 2 for <em>x</em>
g(2) = 2² + 5
g(2) = 4 + 5
g(2) = 9
